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2 years ago

The carbon atoms in graphite and the carbon atoms in Diamond have different

1 answer:

8 0

It's the actual structure of diamond which made the two different. Diamonds have a tetrahedral structure, and as for graphite, it's not structured in that way. The structures of the two is also the reason why diamond is harder than graphite.

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A small cylinder of helium gas used for filling balloons has a volume of 2.20 L and a pressure of 14300 kPa at 25 ∘C. Part A How

Korvikt [17]

Answer:

You can fill 212 balloons.

Explanation:

First we calculate the helium moles in the small cylinder, using PV=nRT:

P = 14300 kPa ⇒ 14300 * 0.009869 = 141.13 atm

V = 2.20 L

n = ?

R = 0.082 atm·L·mol⁻¹·K⁻¹

T = 25 °C ⇒ 25 + 273.16 = 298.16 K

141.13 atm * 2.20 L = n * 0.082 atm·L·mol⁻¹·K⁻¹ * 298.16 K

n = 12.70 mol

Then we calculate the number of moles that can fit in a single balloon:

1.22 atm * 1.20 L = n * 0.082 atm·L·mol⁻¹·K⁻¹ * 298.16 K

n = 0.0599 mol

Finally we divide the total number of available moles by the number of moles in a single balloon:

12.70 mol / 0.0599 mol = 212.09

So the answer is that you can fill 212 balloons.

7 0

2 years ago

In a voltaic cell, the salt bridge acts to:

AleksAgata [21]

Provide a direct contact between the oxidation and reduction electrodes - A

6 0

3 years ago

Read 2 more answers

The distance time graph for four objects is shown below:

solmaris [256]

Answer:

Option A

Explanation:

Remember constant means staying the same so in order to remain constant on the graph the line has to keep going up remaining the same pace. Which means the answer is option A or "Object A." The graph consists of a line going up at a constant speed without any bends or turns which all the other options consist of.

Hope this helps.

6 0

2 years ago

The Handbook of Chemistry and Physics gives solubilities of the following compounds in grams per 100 mL water. Because these com

Elanso [62]

Answer:

(a) $Ksp=4.50x10^{-7}$

(b) $Ksp=1.55x10^{-6}$

(d) $Ksp=1.05x10^{-22}$

Explanation:

Hello,

In this case, given the solubility of each salt, we can compute their molar solubilities by using the molar masses. Afterwards, by using the mole ratio between ions, we can compute the concentration of each dissolved and therefore the solubility product:

(a) $BaSeO_4(s)\rightleftharpoons Ba^{2+}(aq)+SeO_4^{2-}(aq)$

$Molar\ solubility=\frac{0.0188g}{100mL} *\frac{1mol}{280.3g}*\frac{1000mL}{1L}=6.7x10^{-4}\frac{mol}{L}$

In such a way, as barium and selenate ions are in 1:1 molar ratio, they have the same concentration, for which the solubility product turns out:

$Ksp=[Ba^{2+}][SeO_4^{2-}]=(6.7x10^{-4}\frac{mol}{L} )^2\\\\Ksp=4.50x10^{-7}$

(B) $Ba(BrO_3)_2(s)\rightleftharpoons Ba^{2+}(aq)+2BrO_3^{-}(aq)$

$Molar\ solubility=\frac{0.30g}{100mL} *\frac{1mol}{411.15g}*\frac{1000mL}{1L}=7.30x10^{-3}\frac{mol}{L}$

In such a way, as barium and bromate ions are in 1:2 molar ratio, bromate ions have twice the concentration of barium ions, for which the solubility product turns out:

$Ksp=[Ba^{2+}][BrO_3^-]^2=(7.30x10^{-3}\frac{mol}{L})(3.65x10^{-3}\frac{mol}{L})^2\\\\Ksp=1.55x10^{-6}$

$Molar\ solubility=\frac{0.038g}{100mL} *\frac{1mol}{289.35g}*\frac{1000mL}{1L}=1.31x10^{-4}\frac{mol}{L}$

In such a way, as ammonium, magnesium and arsenate ions are in 1:1:1 molar ratio, they have the same concentrations, for which the solubility product turns out:

$Ksp=[NH_4^+][Mg^{2+}][AsO_4^{3-}]^2=(1.31x10^{-4}\frac{mol}{L})^3\\\\Ksp=2.27x10^{-12}$

(D) $La_2(MoOs)_3(s)\rightleftharpoons 2La^{3+}(aq)+3MoOs^{2-}(aq)$

$Molar\ solubility=\frac{0.00179g}{100mL} *\frac{1mol}{1136.38g}*\frac{1000mL}{1L}=1.58x10^{-5}\frac{mol}{L}$

In such a way, as the involved ions are in 2:3 molar ratio, La ion is twice the molar solubility and MoOs ion is three times it, for which the solubility product turns out:

$Ksp=[La^{3+}]^2[MoOs^{-2}]^3=(2*1.58x10^{-5}\frac{mol}{L})^2(3*1.58x10^{-5}\frac{mol}{L})^3\\\\Ksp=1.05x10^{-22}$

Best regards.

7 0

3 years ago

The r group or side chain of the amino acid serine is –ch2 -oh. the r group or side chain of the amino acid alanine is – ch3 . w

olya-2409 [2.1K]

Ch 5 protein mainfactured by solution

8 0

3 years ago