What is diffrent betwenn newtonian and non newtonian?

Chemistry

1 answer:

-BARSIC- [3]3 years ago

5 0

Answer:

Newtonian fluids have a constant viscosity that does not change and non newtonain fluids have a viscosity that varies.

Explanation

Newtonian fluids have a constant viscosity and a zero shear rate at zero shear stress. Non-Newtonian fluids have a variable viscosity and a varible relationship with shear stress.

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What are the oxidation numbers for groups 1-18 (skip groups 3-12)

Brilliant_brown [7]

Group 1: +1
Group 2: +2
Group 13: +3
Group 14: +4
Group 15: -3
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4 0

3 years ago

Read 2 more answers

Calculate the freezing point (in degrees C) of a solution made by dissolving 7.99 g of anthracene{C14H10} in 79 g of benzene. Th

mario62 [17]

Answer: The freezing point of solution is 2.6°C

Explanation:

To calculate the depression in freezing point, we use the equation:

$\Delta T_f=iK_fm$

Or,

$\Delta T_f=i\times K_f\times \frac{m_{solute}\times 1000}{M_{solute}\times W_{solvent}\text{ in grams}}$

where,

$\Delta T_f$ = $\text{Freezing point of pure solution}-\text{Freezing point of solution}$

Freezing point of pure solution = 5.5°C

i = Vant hoff factor = 1 (For non-electrolytes)

$K_f$ = molal freezing point depression constant = 5.12 K/m = 5.12 °C/m

$m_{solute}$ = Given mass of solute (anthracene) = 7.99 g

$M_{solute}$ = Molar mass of solute (anthracene) = 178.23 g/mol

$W_{solvent}$ = Mass of solvent (benzene) = 79 g

Putting values in above equation, we get:

$5.5-\text{Freezing point of solution}=1\times 5.12^oC/m\times \frac{7.99\times 1000}{178.23g/mol\times 79}\\\\\text{Freezing point of solution}=2.6^oC$