When t=2, the ball has fallen d(2) = 16 (2²) = 64 feet .
When t=5, the ball has fallen d(5) = 16 (5²) = 400 feet .
Distance fallen from t=2 until t=5 is (400 - 64) = 336 feet.
Time period between t=2 until t=5 is (5 - 2) = 3 seconds.
Average speed of the ball from t=2 until t=5 is
(distance covered) / (time to cover the distance)
= 336 feet / 3 seconds = 112 feet per second.
That's what choice-C says.
the object has kinetic energy, because it is on the move!!
Give me some answer choices and i will be happy to help
Answer:
6.58×10⁻¹⁸ J
Explanation:
Applying
E = kq²/r.................. Equation 1
Where E = potential energy, q = charge on each electron, r = distance between the electron, k = coulomb's constant.
From the question,
Given: r = 3.5×10⁻¹¹ m,
Constant: q = 1.6×10⁻¹⁹ C, k = 8.99×10⁹ Nm²/C²
Substitute these values into equation 1
E = (1.6×10⁻¹⁹)²(8.99×10⁹)/(3.5×10⁻¹¹)
E = 6.58×10⁻¹⁸ J
Answer:
15.3 m/s
Explanation:
Radius of orbit= 6400+6300 = 12700 km
Circumference of orbit= 2*(22/7)*12700 =79796.45*10^3 m
Now,
Speed= Distance / Time
= 79796.45*10^3/(24*60*3600)
= 15.3 m/s
