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Lapatulllka [165]
4 years ago
11

determine the potential difference between two charged parallel plates that are .10 cm apart and have an electric field strength

of 12V/cm
Physics
1 answer:
mote1985 [20]4 years ago
6 0
The potential difference between two parallel plates is related to the electric field intensity by
\Delta V = Ed
where
\Delta V is the potential difference
E is the electric field intensity
d is the distance between the two plates.

In our problem,
d=0.10 cm
and 
E=12 V/cm
so we can calculate the potential difference as
\Delta V= Ed = (12 V/cm)(0.10 cm)=1.2 V
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