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Lapatulllka [165]

4 years ago

11

determine the potential difference between two charged parallel plates that are .10 cm apart and have an electric field strength

of 12V/cm

1 answer:

mote1985 [20]4 years ago

6 0

The potential difference between two parallel plates is related to the electric field intensity by
$\Delta V = Ed$
where
$\Delta V$ is the potential difference
E is the electric field intensity
d is the distance between the two plates.

In our problem,
$d=0.10 cm$
and
$E=12 V/cm$
so we can calculate the potential difference as
$\Delta V= Ed = (12 V/cm)(0.10 cm)=1.2 V$

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