Explanation:
It is given that,
Initial vapor pressure, P₁ = 77.86 mm
Initial temperature, T₁ = 318.3 K
Final vapor pressure, P₂ = 161.3 mm
Initial temperature, T₂ = 340.7 K
We need to find its heat of vaporization. It can be calculated by using Clausius-Clapeyron equation.
So, the heat of vaporization of a substance is 29.31 kJ/mol. Hence, this is the required solution.
Answer:
2940.1 joules would you burn in climbing stairs all day.
Explanation:
Work = W = F d
going up stairs would be against force of gravity
W = mgh
where h is the height
the question is not complete because we need speed or distance
h = v t
so assuming 1 step per second
h = 86,400 steps 7inchs/step
0.0254 m/inch
h = 15362 m
so from this
W = 800 N 15362
= 12289600 J
that means YOU need 12289600 J to walk 1 step per second all day
divide that by 4180 J /Kcal
Kcal =
=
= 2940.1 Kcal
if you ran faster you would use more energy 2 steps per second would mean 5880 Kcal.