Answer:
The circular solar orbital speed at 4.0AU is 1/4( one fourth) that at 1.0AU
Explanation:
am = mvr= angular momentum
am4= 4mvt
am1= mvp1
Vt=1/4vp
Vp=4vt
am1= 4mvt
am1=am4
The circular solar orbital speed at 4.0AU is 1/4 (one fourth) that at 1.0AU
As the surface given is a smooth surface, we can use specular reflection. According to the law of specular reflection, the angle of incidence equals the angle of reflection, so it will also be 40°. Answer is A.
The correct answer would be the sun
Answer:
efficiency of engine is 0.21
Explanation:
given:
Th=980 K
Tc=570 K
since efficiency of engine is given as:
n=3/5*n_m
=3/5(1-Tc/Th)
=0.21
efficiency of engine is 0.21
Answer:
5.9 km/hour
Explanation:
divide 12.5 by 2.1 and the answer is 5.9
