Answer:
Step-by-step explanation:
yes its good
Answer:
150 miles
distance travelled on the third day = 150 miles
Step-by-step explanation:
Note: it was given that they drove the same speed throughout the trip. That means their speed is constant for all days;
For the first day
distance = 300 miles
time = 6 hours
Speed = distance/time
Speed = 300/6 = 50 mph
on the third day;
time = 3 hours
Speed = speed on first day = 50 mph
distance = speed × time
distance = 50 mph × 3 hours
distance = 150 miles
distance travelled on the third day = 150 miles
Answer:
2.
Step-by-step explanation:
For #2, another way to word this question is: For which of the following trig functions is π/2 a solution? Well, go through them one by one. If you plug π/2 into sinθ, you get 1. This means that when x is π/2, y is 1. Try and visualize that. When y is 1, that means you moved off the x-axis; so y = sinθ is NOT one of those functions that cross the x-axis at θ = π/2. Go through the rest of them. For y = cos(π/2), you get 0. At θ = π/2, this function crosses the x-axis. For y = tanθ, your result is undefined, so that doesn't work. Keep going through them. You should see that y = secθ is undefined, y = cscθ returns 1, and y = cotθ returns 0. If you have a calculator that can handle trig functions, just plug π/2 into every one of them and check off the ones that give you zero. Graphically, if the y-value is 0, the function is touching/crossing the x-axis.
Think about what y = secθ really means. It's actually y = 1/(cosθ), right? So what makes a fraction undefined? A fraction is undefined when the denominator is 0 because in mathematics, you can't divide by zero. Calculators give you an error. So the real question here is, when is cosθ = 0? Again, you can use a calculator here, but a unit circle would be more helpful. cosθ = π/2, like we just saw in the previous problem, and it's zero again 180 degrees later at 3π/2. Now read the answer choices.
All multiples of pi? Well, our answer looked like π/2, so you can skip the first two choices and move to the last two. All multiples of π/2? Imagine there's a constant next to π, say Cπ/2 where C is any number. If we put an even number there, 2 will cut that number in half. Imagine C = 4. Then Cπ/2 = 2π. Our two answers were π/2 and 3π/2, so an even multiple won't work for us; we need the odd multiples only. In our answers, π/2 and 3π/2, C = 1 and C = 3. Those are both odd numbers, and that's how you know you only need the "odd multiples of π/2" for question 3.
We are given the vertices of the triangle with their respective coordinates. For the vertex L, the translated coordinates is also given. So, from the original coordinates of L and the new coordinates, we can get the rule used during translation:(7, -3) -> (7 + a, -3 + b) = (-1, 8)7 + a = -1a = -8
-3 + b = 8b = 11
Therefore, the answer is:(x, y) → (x – 8, y + 11)
