Answer:
The time it can operate between chargins in minutes is
Explanation:
Given: , ,
a). The rotational kinetic energy
b). The power average 0.8kW un range time can be find
Solve to t'
Let's call
N=Normal force.
m*g=Weight.
F= Force needed to move the block.
f = friction force.
k = static friction coefficient.
For balance:
N = mg and F = f
By definition
f=k*N.
Clearing this last expression:
k=f/N.
Substituting:
k=f/N=F/m*g=(47)/((13)*(9.8))=0.37
the coefficient of static friction between the box and floor is 0.37
Answer:
3.43 x 10⁵ N/m
Explanation:
M = mass of the car alone = 2000 kg
m = mass of the four people combined = 315 kg
x = compression of the spring when there is car alone
x' = compression of the spring when there is car and four people = x + 0.009
k = spring constant
When there is car, the weight of the car is balanced by the spring force and the force equation is given as
k x = Mg
k x = (2000)(9.8)
k x = 19600 eq-1
When there is car and four people, the weight of the car and four people is balanced by the spring force and the force equation is given as
k x' = (M + m) g
k (x + 0.009) = (2000 + 315) (9.8)
k x + 0.009 k = (2000 + 315) (9.8)
using eq-1
19600 + 0.009 k = 22687
k = 3.43 x 10⁵ N/m
Answer:
The minimum difference between the lengths of the two tubes should be 0.385 meters.
Explanation:
As we known that for any two waves to arrive in phase at any point the difference in the path traveled by the waves should be an integral multiple of the wavelength of the wave.
Mathematically we can write:
For the given wave we have
Applying values we get
Thus the minimum difference in the lengths of the tubes can be obtained by putting the value of n = 1