Answer: r = 1.33 × 10^-5 mm
Explanation: The force per unit length of 2 current carrying conductor is given by the formulae below.
F/L = (u×I1×I2) /(2πr)
Where F/L = force per unit length = 7.73×10^-5mm = 0.0775 mm.
I1 = current on the first conductor = 4.27A
I2 = current on the second conductor = 1.19A
r = distance between both conductors.
u = permeability of free space = 1.25×10^-6
By substituting parameters, we have that
0.0775 = 1.25×10^-6 × 4.27 × 1.19/ 2πr
By cross multiplication
0.0775 ×2πr = 1.25×10^-6 × 4.27 × 1.19
r = 1.25×10^-6 × 4.27 × 1.19/ 0.0775 ×2π
r = 0.00000635162 / 0.0775 ×2π
r = 1.33 × 10^-5 mm
<h2>
Answer: 502.08 J</h2>
Explanation:
The heat (thermal energy) needed in to raise the temperature in a process can be found using the following equation:
(1)
Where:
is the heat
is the mass of the element (<u>water</u> in this case)
is the specific heat capacity of the material. In the case of water is
is the variation in temperature <u>(which is increased in this case)</u>
Knowing this, let's rewrite (1) with these values:
(2)
Finally:
Yes bc you can get electricuted
Answer:
the angle is about 67.79 degrees
Explanation:
We know that at its maximum height, the vertical component of the projectile's launching (initial) velocity (Vyi) is zero, so at that point it total velocity equals the horizontal component of the initial velocity (Vxi = 0.5 m/s)
We also know that the maximum height of the projectile is given by the square of its initial vertical component of the velocity (Vyi) divided by 2g, therefore half of such distance is :
we can use this information to find the y component of the velocity at that height via the formula:
Now we use the information that tells us the speed of the projectile at this height to be 1 m/s. That should be the result of the vector addition of the vertical and horizontal components:
Now we can use the arc-tangent to calculate the launching angle, since we know the two initial component of the velocity vector: