The steps in the patterns A and B form a sequence
The attached diagram represents dots in patterns A and B
<h3>How to draw the diagrams</h3>
For pattern A, we have:
Step 2 = 10 dots
Increment of 3 dots in each step
This means that:
Step 0 = 4 dots
Step 1 = 7 dots
Step 2 = 10 dots
Step 3 = 13 dots
For pattern A, we have the following rule
![T_n =2n^2 + 1](https://tex.z-dn.net/?f=T_n%20%3D2n%5E2%20%2B%201)
When n = 0 to 3, we have:
![T_0 =2(0)^2 + 1 =1](https://tex.z-dn.net/?f=T_0%20%3D2%280%29%5E2%20%2B%201%20%3D1)
Step 0 = 1 dot
![T_1 =2(1)^2 + 1 =3](https://tex.z-dn.net/?f=T_1%20%3D2%281%29%5E2%20%2B%201%20%3D3)
Step 1 = 3 dots
![T_2 =2(2)^2 + 1 =9](https://tex.z-dn.net/?f=T_2%20%3D2%282%29%5E2%20%2B%201%20%3D9)
Step 2 = 9 dots
![T_3 =2(3)^2 + 1 =19](https://tex.z-dn.net/?f=T_3%20%3D2%283%29%5E2%20%2B%201%20%3D19)
Step 3 = 19 dots
Next, we draw the diagrams of both patterns (see attachment)
Read more about patterns at:
brainly.com/question/15590116
The answer would be +3 since ur adding 3 every time
Answer:
the answer is the last one
Step-by-step explanation:
The denominator has to be the total number of kids and the numerator is the kids that can stay after school. so 12/30 then simplify. 12/30 divided by 6/6 = 2/5
Answer:
5.1666666666667
To solve ✅
We know that...
![5\frac{1}{6} = 5 + \frac{1}{6}](https://tex.z-dn.net/?f=5%5Cfrac%7B1%7D%7B6%7D%20%3D%205%20%2B%20%5Cfrac%7B1%7D%7B6%7D)
So that means
= 1 ÷ 6
And with that info, 5 1/6 becomes
![5 + (\frac{1}{6})](https://tex.z-dn.net/?f=5%20%2B%20%28%5Cfrac%7B1%7D%7B6%7D%29)
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Solve by improper fractions ➗
We know from the last problem that...
![5\frac{1}{6} = 5 + \frac{1}{6}](https://tex.z-dn.net/?f=5%5Cfrac%7B1%7D%7B6%7D%20%3D%205%20%2B%20%5Cfrac%7B1%7D%7B6%7D)
Converting 5 as a whole number to a fraction, it becomes
![5 = \frac{5}{1}](https://tex.z-dn.net/?f=5%20%3D%20%5Cfrac%7B5%7D%7B1%7D)
Now it becomes...
![\frac{5}{1} + \frac{1}{6}](https://tex.z-dn.net/?f=%5Cfrac%7B5%7D%7B1%7D%20%2B%20%5Cfrac%7B1%7D%7B6%7D)
Since the fractions will not change, first find the whole, then multiply your improper fraction by the whole, and add the part
![\frac{6}{6}\\\\ = (\frac{5}{1} * \frac{6}{6} ) + \frac{1}{6}](https://tex.z-dn.net/?f=%5Cfrac%7B6%7D%7B6%7D%5C%5C%5C%5C%20%3D%20%28%5Cfrac%7B5%7D%7B1%7D%20%2A%20%5Cfrac%7B6%7D%7B6%7D%20%29%20%2B%20%5Cfrac%7B1%7D%7B6%7D)
Converting to improper fraction
<em>never add the denominators when they are equal.</em>
We know that...
= 31 ÷ 6
Whose quotient is equal to
![5.166](https://tex.z-dn.net/?f=5.166)
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