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gogolik [260]
3 years ago
9

How much barium chloride is needed to prepare 250 cm cube of 0.500 M bacl2 solution​

Chemistry
1 answer:
CaHeK987 [17]3 years ago
5 0
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You might be interested in
Can someone pls help me with this question
artcher [175]

Answer:

The answer to your question is 24.325

Explanation:

Data

Magnesium-24  Abundance = 78.70%

Magnesium-25  Abundance = 10.13%

Magnesium-26  Abundance = 11.17%

Process

1.- Convert the abundance to decimals

Magnesium-24  Abundance = 78.70/100 = 0.787

Magnesium-25  Abundance = 10.13/100 = 0.1013

Magnesium-26  Abundance = 11.17/100 = 0.1117

2.- Write an equation

Average atomic mass = (Atomic mass-1 x Abundance 1) + (Atomic mass 2 x

                                       Abundance-2) + (Atomic mass 3 x Abundance 3)

3.- Substitution

Average atomic mass = (24 x 0.787) + (25 x 0.1013) + (26 x 0.1117)

4.- Simplification

Average atomic mass = 18.888 + 2.533 + 2.904

5.- Result

Average atomic mass = 24.325

5 0
4 years ago
A piece of solid carbon dioxide with a mass of 5.50 grams is placed in a 10 Liter vessel that already contains 705 torr at 24 Ce
alex41 [277]

total pressure = ( 705 torr + 231.525torr)  =   936.525torr

7 0
3 years ago
Read 2 more answers
2. if 0.20 m fe3 had been used instead of 0.020 m fe3 , how would the numerical value of the rate constant and the activation en
dezoksy [38]

the calculated value is Ea is 18.2 KJ and A is 12.27.

According to the exponential part in the Arrhenius equation, a reaction's rate constant rises exponentially as the activation energy falls. The rate also grows exponentially because the rate of a reaction is precisely proportional to its rate constant.

At 500K, K=0.02s−1

At 700K, k=0.07s −1

The Arrhenius equation can be used to calculate Ea and A.

RT=k=Ae Ea

lnk=lnA+(RT−Ea)

At 500 K,

ln0.02=lnA+500R−Ea

500R Ea (1) At 700K lnA=ln (0.02) + 500R

lnA = ln (0.07) + 700REa (2)

Adding (1) to (2)

700REa100R1[5Ea-7Ea] = 0.02) +500REa=0.07) +700REa.

=ln [0.02/0 .07]

Ea= 2/35×100×8.314×1.2528

Ea =18227.6J

Ea =18.2KJ

Changing the value of E an in (1),

lnA=0.02) + 500×8.314/18227.6

= (−3.9120) +4.3848

lnA=0.4728

logA=1.0889

A=antilog (1.0889)

A=12.27

Consequently, Ea is 18.2 KJ and A is 12.27.

Learn more about Arrhenius equation here-

brainly.com/question/12907018

#SPJ4

5 0
1 year ago
2. If 1.75 L of a gas is at 700. K and is under 250. kPa of pressure, what will the new
Andrews [41]

Answer:

Final volume is 3.50L

Explanation:

It is possible to find volume of a gas using combined gas law:

\frac{P_1V_1}{T_1} =\frac{P_2V_2}{T_2}

<em>Where P is pressure, V is volume and T is temperature of 1: initial state and 2: final state</em>

If initial state of the gas is:

1.75L of a gas is at 700K and is under 250kPa of pressure

And final state is:

298K and 53.2kPa.

Replacing:

\frac{250kPa*1.75L}{700K} =\frac{53.2kPa*V_2}{298K}

0.625L = 0.1785*V₂

<em>3.50L = V₂</em>

Thus, <em>final volume is 3.50L</em>

3 0
3 years ago
The ___ variable responds to the __ variable and goes on the Y-axis.
ale4655 [162]

Answer: 1. Dependent, Independent The dependent variable responds to the independent variable and goes on the Y-axis.

Explanation: The independent variable is controlled or manipulated by the experimenter. For example, someone's age might be an independent variable. Other factors (such as what they eat, how much they go to school, how much television they watch) aren't going to change a person's age.The dependent variable is what you are measuring. For example, a test score could be a dependent variable because it could change depending on several factors such as how much you studied, how much sleep you got the night before you took the test, or even how hungry you were when you took it.

How that helps. :)

3 0
3 years ago
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