Answer:
30 moles of CO₂
Explanation:
balanced equation ,
CS₂+3O₂ → CO₂+2SO₂
From equation, 3 moles of O₂ are needed to make 1 mol of CO₂.
This means to produce 1 mol of CO₂, we need 3 moles of O₂, then how many moles of CO₂ will be produced from 90 moles of O₂ ?
Use unitary method to solve such problems,
Number of moles of CO₂ that will be produced:
= 
=
= 30 moles of CO₂
Answer:
Explanation:
Percent means " per hundred," so % m/V means the grams of something in 100 mL of volume.
Data:
m/V % = 2.20 %
V of solution = 250 mL
Calculations:
Answer:
S is the limiting reagent.
Explanation:
To find the limiting reactant we must first write the balanced chemical reaction. It must be correctly balanced so that we can find the proper mole ratios.
2 S (s) + 3 O2 (g) + 4 NaOH (aq) → 2 Na2SO4 (aq) + 2 H2O (l)
After this we will convert our measurements to moles. For mass we do this by dividing by the molar mass.
2g ÷ 32.06 = 0.06238mol S
3g ÷ 32.00 = 0.09375mol O₂
Now that we have the moles of each of the reactants, we can multiply them by their mole ratio with a reactant.
0.06238mol S × 2/2 = 0.06238mol H2O
0.09375mol O₂ × 2/3 = 0.06250mol H2O
S is our limiting reagent because it makes the smaller amount of moles.
