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Shkiper50 [21]
3 years ago
5

Ella used 3 4 of a bag of lemons to make 1 2 liters of lemonade. If Ella's recipe is for 1 liter of lemonade, how many lemons wi

ll she need to make 4 times the recipe?
Mathematics
2 answers:
suter [353]3 years ago
6 0

Answer:

ANSWER IS B

Step-by-step explanation:

To find the unit rate: multiply the numerator by the reciprocal of the denominator.

unit rate = 3 /4 /1 /2  =  3/ 4  ×  2 /1  =  6 /4  =  3 /2  bags per liter

Therefore, 4 times the recipe:  

3 /2  × 4 = 6 bags of lemons

Sergeeva-Olga [200]3 years ago
3 0

<u>Answer:</u>

Ella will need 6 lemons for 4 times the recipe

<u>Explanation:</u>

Given Ella used ¾ of a bag of lemon to make ½ liters of lemonade

Therefore, we can form an equation as:

¾ bag lemons = ½ liter lemonade

According to question,

Ella recipe is for 1 liter of lemonade

Lemons required for ½ liter lemonade = \frac{3}{4} bag

Lemons required for 1 liter lemonade =\frac{3}{4}\times 2 = 3/2 bags

To make 4 times the recipe, she will require,

\frac{3}{2} \times 4 = 3 \times 2 = 6

She will need 6 lemons for 4 times the recipe

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Ilia_Sergeevich [38]

Answer:

D) 57.5°

Step-by-step explanation:

As the question is not complete. So, let's suppose it is a right angle triangle then, we can apply Pythagoras theorem to calculate the hypotenuse or the third side.

Pythagoras Theorem = c^{2} = a^{2} + b^{2}

a = 7 and b = 11

a^{2} = 49

b^{2} = 121

Plugging in the values, we will get:

c^{2} = 49 + 121

c^{2} = 170

c = \sqrt{170}

To calculate the unknown angle B, we can use law of sine.

Law of sine = \frac{a}{sinA} = \frac{b}{sinB} = \frac{c}{sinC}

So,

\frac{c}{sinC} = \frac{b}{sinB}

\frac{\sqrt{170} }{sin90} =  \frac{11}{sinB}

Sin90 = 1

sinB = \frac{11}{\sqrt{170} }

B = sin^{-1} (\frac{11}{\sqrt{170} })

B = 57.5°

8 0
3 years ago
What is the equation of the line, in slope-intercept form, that passes through (3, -1) and (-1, 5)? y = - 2y = -3x + 7 2x + 3y -
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The line passing through (3, -1) and (-1, 5) has this slope:

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Answer:

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Summation symbol '\sum'

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