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Rudiy27
2 years ago
15

I NEED HELP!!! PLEASE!!! 2 + 2 = ?

Mathematics
2 answers:
Arte-miy333 [17]2 years ago
8 0

Answer: 4

Step-by-step explanation: the answer is 50,005 :)

hehe maybe the answer is 4

natita [175]2 years ago
4 0

Answer:

4 or monke

Step-by-step explanation:

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The length of a rectangle is increasing at a rate of 4 meters per day and the width is increasing at a rate of 1 meter per day.
puteri [66]

Answer:

\displaystyle \frac{dA}{dt} = 102 \ m^2/day

General Formulas and Concepts:

<u>Pre-Algebra</u>

Order of Operations: BPEMDAS

  1. Brackets
  2. Parenthesis
  3. Exponents
  4. Multiplication
  5. Division
  6. Addition
  7. Subtraction
  • Left to Right<u> </u>

<u>Geometry</u>

Area of a Rectangle: A = lw

  • l is length
  • w is width

<u>Calculus</u>

Derivatives

Derivative Notation

Implicit Differentiation

Differentiation with respect to time

Derivative Rule [Product Rule]:                                                                              \displaystyle \frac{d}{dx} [f(x)g(x)]=f'(x)g(x) + g'(x)f(x)

Step-by-step explanation:

<u>Step 1: Define</u>

<u />\displaystyle l = 10 \ meters<u />

<u />\displaystyle \frac{dl}{dt} = 4 \ m/day<u />

<u />\displaystyle w = 23 \ meters<u />

<u />\displaystyle \frac{dw}{dt} = 1 \ m/day<u />

<u />

<u>Step 2: Differentiate</u>

  1. [Area of Rectangle] Product Rule:                                                                 \displaystyle \frac{dA}{dt} = l\frac{dw}{dt} + w\frac{dl}{dt}

<u>Step 3: Solve</u>

  1. [Rate] Substitute in variables [Derivative]:                                                    \displaystyle \frac{dA}{dt} = (10 \ m)(1 \ m/day) + (23 \ m)(4 \ m/day)
  2. [Rate] Multiply:                                                                                                \displaystyle \frac{dA}{dt} = 10 \ m^2/day + 92 \ m^2/day
  3. [Rate] Add:                                                                                                      \displaystyle \frac{dA}{dt} = 102 \ m^2/day

Topic: AP Calculus AB/BC (Calculus I/II)

Unit: Implicit Differentiation

Book: College Calculus 10e

8 0
3 years ago
Which equation has a constant of proportionality equal to
seraphim [82]

There are many equations that has a constant of

proportionality, might want to make it more specific.

5 0
3 years ago
Question #8 help me plz
valina [46]

Answer:

UH HOLD ON RIGHT QUICK CAN YOU TELL ME THE QUESTION  

Step-by-step explanation:

4 0
2 years ago
A professor's son, having made the wise decision to drop out of college, has been finding his way in life taking one job or anot
Trava [24]

Answer:

88.88% probability that it endures for less than a year and a half

Step-by-step explanation:

Problems of normally distributed samples can be solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the zscore of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

In this question, we have that:

\mu = 66, \sigma = 10

The next career begins on Monday; what is the likelihood that it endures for less than a year and a half?

One year has 52.14 weeks. So a year and a half has 1.5*52.14 = 78.21 weeks.

So this probability is the pvalue of Z when X = 78.21.

Z = \frac{X - \mu}{\sigma}

Z = \frac{78.21 - 66}{10}

Z = 1.22

Z = 1.22 has a pvalue of 0.8888

88.88% probability that it endures for less than a year and a half

6 0
3 years ago
What’s a problem with no solution
Free_Kalibri [48]

When a problem has no solution you'll end up with a statement that's <em>false</em>. For example: 0=1 This is false because we know zero can't equal one. Therefore we can conclude that the problem has no solution.

6 0
2 years ago
Read 2 more answers
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