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Orlov [11]
2 years ago
7

A balloon contains 0.15 moles of co2 gas. how many molecules of co2 are in the balloon?

Chemistry
2 answers:
Leno4ka [110]2 years ago
7 0

The number of atoms or molecules in one mole of a substance is defined as Avagadro's number

The Avagadro's number is 6.023 X 10^23 atoms / molecules

Given:

The moles of carbon dioxide = 0.15 moles

In order to calculate the number of molecules in given moles of carbon dioxide we will multiply the given moles with Avagadro's number as

Number of molecules = 0.15 X 6.023 X 10^23

Number of molecules = 9.035 X 10^22 molecules of carbon dioxide

Sauron [17]2 years ago
5 0
1- One mole is = 6.02 x 10^23 of anything, So one mole of atoms is 6.02x10^23.

2- when the balloon contains 0.15 moles of Co2 gas so:

the no.of molecules of Co2 = 0.15 x 6.02x 10^23

                                              = 9.0 x 10^22
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Write ionic equations for any three of the following:
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1.

The ionic equation is:

H⁺(aq) + NO₃⁻(aq) + Na⁺(aq) + OH⁻(aq) → Na⁺(aq) + NO₃⁻(aq) + H₂O(l)

HNO₃(aq) + NaOH(aq) → NaNO₃(aq) + H2O(l)

The required dissociations are

HNO₃(aq) → H⁺(aq) + NO₃⁻(aq)

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NaNO₃(aq) → Na⁺(aq) + NO₃⁻(aq)

So, the ionic equation is

H⁺(aq) + NO₃⁻(aq) + Na⁺(aq) + OH⁻(aq) → Na⁺(aq) + NO₃⁻(aq) + H₂O(l)

2.

The ionic equation is

H⁺(aq) + Cl⁻(aq) + K⁺(aq) + OH⁻(aq) → K⁺(aq) + Cl⁻(aq) + H₂O(l)

HCl(aq) + KOH(aq) → KCl(aq) + H2O(l)

The required dissociations are

HCl(aq) → H⁺(aq) + Cl⁻(aq)

KOH(aq) → K⁺(aq) + OH⁻(aq)

KCl(aq) → K⁺(aq) + Cl⁻(aq)

So, the ionic equation is

H⁺(aq) + Cl⁻(aq) + K⁺(aq) + OH⁻(aq) → K⁺(aq) + Cl⁻(aq) + H₂O(l)

3.

The ionic equation is

2H⁺(aq) + SO₄²⁻(aq) + Mg²⁺(aq) + 2OH⁻(aq) → Mg²⁺(aq) + SO₄²⁻(aq)

+ 2H₂O(l)

H₂SO₄(aq) + Mg(OH)₂(aq) → MgSO₄(aq) + 2H2O(l)

The required dissociations are

H₂SO₄(aq) → 2H⁺(aq) + SO₄²⁻(aq)

Mg(OH)₂(aq) → Mg²⁺(aq) + 2OH⁻(aq)

MgSO₄(aq) → Mg²⁺(aq) + SO₄²⁻(aq)

So, the ionic equation is

2H⁺(aq) + SO₄²⁻(aq) + Mg²⁺(aq) + 2OH⁻(aq) → Mg²⁺(aq) + SO₄²⁻(aq)

+ 2H₂O(l)

Learn more about ionic equations here:

brainly.com/question/11628165

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It is given that density of graphite is 2.16 g/cm^{3} or 2160 kg/m^{3}.

So, W = 2160 V g

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Hence, in second weighing total mass will be calculated as follows.

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