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3 years ago

Can a soccer goalkeeper score a goal in his own goal.

Physics

1 answer:

kupik [55]3 years ago

4 0

Answer:

Explanation:

A goal can be scored directly from a goal kick against the opposing team. An own goal cannot be scored from a goal kick; in the highly unlikely circumstance that the ball enters the kicker's own goal before being touched by another player, a corner kick is awarded.

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A spring has a length of 0.200 m when a 0.300-kg mass hangs from it, and a length of 0.750 m when a 1.95-kg mass hangs from it.

Juli2301 [7.4K]

Answer:

Explanation:

The change in force = 9.81(1.95 - 0.300) = 16.2 N

The change in length is 0.750 - 0.200 = 0.550 m

K = ΔF/Δx = 16.2/0.550 = 29.4 N/m

5 0

2 years ago

Calculate the density of a solid of mass 20kg if it occupies a volume of 4m³

choli [55]

Answer:

Density=Mass/Volume

=20/4 kg/m^3

=5 kg/m^3

4 0

3 years ago

An astronaut carrying a camera in space finds herselfdrifting away from a space shuttle after her tetherbecomes unfastened. If s

Dahasolnce [82]

Answer:

Explanation:

According to the conservation of momentum, if she throws the camera in the opposite direction of space shuttle, she drifts towards the shuttle.

5 0

3 years ago

How does the image make the message in the "Mummy, what happens to us if the bomb drops?" poster more clear?

Nimfa-mama [501]

Answer:

C. The poster provides an emotional picture of a young, innocent girl with a slightly worried expression to make protective feelings.

Explanation:

The girl looks quite worried in the poster. Attached is the image:

8 0

2 years ago

A 6.00 kg ball is dropped from a height of 12.0 m above one end of a uniform bar that pivots at its center. The bar has mass 5.0

Andre45 [30]

Answer:

The height of the other ball go after the collision is 2.304 m.

Explanation:

Given that,

Mass of ball = 6.00 kg

Height = 12.0 m

Mass of bar =5.00 kg

Length = 4.00 m

Suppose we need to calculate how high will the other ball go after the collision

We need to calculate the velocity of ball

Using formula of velocity

$v=\sqrt{2gh}$

$v=\sqrt{2\times9.8\times12.0}$

$v=15.33\ m/s$

We need to calculate the angular momentum

Using formula of angular momentum

$l_{before}=mvr$

Put the value into the formula

$l_{before}=6.00\times15.33\times2.0$

$l_{before}=183.96\ kgm^2/s$

We need to calculate the angular momentum

Using formula of angular momentum

$l_{after}=I_{t}\omega$

$l_{after}=(\dfrac{ml^2}{12}+m_{1}r^2+m_{2}r^2)\omega$

Put the value into the formula

$l_{after}=(\dfrac{5\times4.00^2}{12}+6.00\times2.0^2+6.00\times2.0^2)\omega$

$183.96=54.66\omega$

$\omega=\dfrac{183.96}{54.66}$

$\omega=3.36\ rad/sec$

After collision the ball leaves with velocity

We need to calculate the velocity after collision

Using formula of the velocity

$v= r\omega$

$v=2.0\times3.36$

$v=6.72\ m/s$

We need to calculate the height

Using formula of height

$h=\dfrac{v^2}{2g}$

Put the value into the formula

$h=\dfrac{(6.72)^2}{2\times9.8}$

$h=2.304\ m$

Hence, The height of the other ball go after the collision is 2.304 m.

5 0

3 years ago