Answer:
The tension is 75.22 Newtons
Explanation:
The velocity of a wave on a rope is:
(1)
With T the tension, L the length of the string and M its mass.
Another more general expression for the velocity of a wave is the product of the wavelength (λ) and the frequency (f) of the wave:
(2)
We can equate expression (1) and (2):
=
Solving for T
(3)
For this expression we already know M, f, and L. And indirectly we already know λ too. On a string fixed at its extremes we have standing waves ant the equation of the wavelength in function the number of the harmonic is:
It's is important to note that in our case L the length of the string is different from l the distance between the pin and fret to produce a Concert A, so for the first harmonic:
We can now find T on (3) using all the values we have:
Answer:
a₁ = 0.63 m/s² (East)
a₂ = -1.18 m/s² (West)
Explanation:
m₁ = 95 Kg
m₂ = 51 Kg
F = 60 N
a₁ = ?
a₂ = ?
To get the acceleration (magnitude and direction) of the man we apply
∑Fx = m*a (⇒)
F = m₁*a₁ ⇒ 60 N = 95 Kg*a₁
⇒ a₁ = (60N / 95Kg) = 0.63 m/s² (⇒) East
To get the acceleration (magnitude and direction) of the woman we apply
∑Fx = m*a (⇒)
F = -m₂*a₂ ⇒ 60 N = -51 Kg*a₂
⇒ a₂ = (60N / 51Kg) = -1.18 m/s² (West)
For every case we apply Newton’s 3
d Law
Answer:
v=wavelength ×f
wavelength=v/f=455/655=0.694m
Answer:
0.465 kgm/s
Explanation:
Given that
Mass of the cart A, m1 = 450 g
Speed of the cart A, v1 = 0.85 m/s
Mass of the cart B, m2 = 300 g
Speed of the cart B, v2 = 1.12 m/s
Now, using the law of conservation of momentum.
It is worthy of note that our cart B is moving in opposite directions to A
m1v1 + m2v2 =
(450 * 0.85) - (300 * 1.12) =
382.5 - 336 =
46.5 gm/s
If we convert to kg, we have
46.5 / 100 = 0.465 kgm/s
Thus, the total momentum of the system is 0.465 kgm/s