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g100num [7]
3 years ago
6

Please help !!!!!!!!!!!!

Physics
2 answers:
Yakvenalex [24]3 years ago
8 0

Answer:

152 Volts

Explanation:

First, the Resistors are in series. So, the net resistance, R = 3 + 4 +3 + 4 +5

= 19 ohms

Using, V = IR;

V (the needed P.D) = 8 x 19 = 152 Volts

will be needed to successfully transport 8 amps of current round the circuit

miv72 [106K]3 years ago
6 0

Answer:

4q

Explanation:

wait nvm i dont know

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The magnitude of the acceleration  is a = 0.33 m/s^2

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         The charge on the particle is q = 1.22*10^{-8}C

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        The the magnetic field is  \= B = (1.63T)\r i + (0.980T) \r j

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                    F = q (\= v * \= B)

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         F = 1.22*10^{-8} (( 3*10^4 ) \r j \ \ X \ \  ( 1.63 \r i  + 0.980 \r j )T)

            = 1.22 *10^{-8} ((3*10^4 * 1.63)(\r j \ \  X \ \  \r i) + (3*10^4 * 0.980) (\r j \ \ X \ \  \r  j))

            = (-5.966*10^4 N) \r k

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           i \ \ X \ \ j = k \\\\j \ \  X  \ \ k = i\\\\k  \ \ X \ \ i = j\\\\j \ \ X \ \ i = -k \\\\k \ \  X  \ \ j = -i\\\\i  \ \ X \ \ k = - j\\

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        F = ma

Making a the subject

      a = \frac{F}{m}

   Substituting values

     a =\frac{(-5.966*10^4) \r k}{1.81*10^{-3}}

        = (-0.33m/s^2)\r k

        = 0.33m/s^2 * (- \r k)

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