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zubka84 [21]
3 years ago
6

A bag contains 8 red M&Ms, 12 blue M&Ms, 3 brown M&Ms, and 7 green M&Ms. An M&M is picked at random from the

bag. What is the probability of getting the first color M&M, eating it, then grabbing the second color? Green, then another green:
Mathematics
1 answer:
Temka [501]3 years ago
7 0

Answer:

7/145

Step-by-step explanation:

7/30x6/29=42/870 = 7/145

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Answer:

0.714 free throws.

Step-by-step explanation:

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This equals 0.714 free throws (answer rounded up to the nearest thousandths)

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<span>(2x-3)/x^2 
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