The size conductor that should be used to supply each motor is 12 AWG and the size conductor that should be used for the feeder conductor is 1/0AWG.
<h3>Size conductor</h3>
a. Using NEC table 430.250
Running connect for 150HP connected to 460V = 21 A
Conductor size=25% current to 125% current (Increase)
Increase current=21×125/100
Increase current=26.25 A
Nearest standard conductor size using NEC table 310.15(B)(16)=25 A
Since the motor contain NEMA design code the conductor will be choosing from 75° column which means that the size conductor that should be used to supply each motor is 12AWG copper conductors.
b. Feeder conductor
Using NEC section 430.24 plus ampere rating of other motors
Running current
Using NEC Table 430.250
Running current=26.25+21+21+21+21+21
Running current=131.25 A
The value that is greater than 131.25 A under 75° column of NEC Table 310 (B)(16) is 150 A which means that the size conductor that should be used for the feeder conductor is 1/0 AWG conductors.
Therefore the size conductor that should be used to supply each motor is 12 AWG and the size conductor that should be used for the feeder conductor is 1/0AWG.
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Answer:
True
Explanation:
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Answer:
Explanation:
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Answer:
See explaination
Explanation:
Please kindly check attachment for the step by step solution of the given problem.
Answer:
the vertical relationship of pitches.
Explanation:
Harmony can be defined as the use of simultaneous pitches ( two or more tones and notes) or chords played at the same time together.
Harmony in music is characterized by the vertical relationship of pitches. The three most popular and essential forms of harmony are;
1. Diatonic harmony.
2. Non-diatonic harmony.
3. Atonal harmony.
