A cyclone is operated in a closed circuit with a ball mill. The cyclone is feed from a rod mill with a slurry that has a density
of 1250 kg/m3 while the solid bulk density is 2900 kg/m3. Cyclone overflow goes to flotation circuit consists of a rougher, a scavenger and one cleaner cell. The slury feed to the rougher has 15% solids (overflow) while the feed to ball mill (underflow) from the cyclone has 50% solids with a mass flow rate of 40 t/h.
• Draw a possible flow sheet of the process
• Calculate the mass flow rate of the feed from rod mill to cyclone (hint: you need to calculate % solids in feed and dilution ratios)
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• Draw a possible flow sheet of the process
• Calculate the mass flow rate of the feed from rod mill to cyclone (hint: you need to calculate % solids in feed and dilution ratios)
Get more help from Chegg
1 answer:
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Answer:
Specific gravity is 0.5 so option (a) is correct option
Explanation:
We have given mass of substance m =10 kg
Volume
Density of substance is given by
Specific gravity is given by
So option (a) is correct option
Answer:
n=2.32
w= -213.9 KW
Explanation:
Mass of air=1 kg
For polytropic process ,n is the polytropic constant.
n=2.32
Work in polytropic process given as
w=
w=
Now by putting the values
w=
w= -213.9 KW
Negative sign indicates that work is given to the system or work is done on the system.
For T_V diagram
We can easily observe that when piston cylinder reach on new position then volume reduces and temperature increases,so we can say that this is compression process.
Answer:
See explaination
Explanation:
for a reverse carnot cycle T-S diagram is a rectangle which i have shown
net work for a complete cycle must be equal to net heat interaction.
Kindly check attachment for the step by step solution of the given problem.
