Answer:
attached below
Explanation:
A cyclone is operated in a closed circuit with a ball mill. The cyclone is feed from a rod mill with a slurry that has a density
of 1250 kg/m3 while the solid bulk density is 2900 kg/m3. Cyclone overflow goes to flotation circuit consists of a rougher, a scavenger and one cleaner cell. The slury feed to the rougher has 15% solids (overflow) while the feed to ball mill (underflow) from the cyclone has 50% solids with a mass flow rate of 40 t/h.
• Draw a possible flow sheet of the process
• Calculate the mass flow rate of the feed from rod mill to cyclone (hint: you need to calculate % solids in feed and dilution ratios)
Get more help from Chegg
• Draw a possible flow sheet of the process
• Calculate the mass flow rate of the feed from rod mill to cyclone (hint: you need to calculate % solids in feed and dilution ratios)
Get more help from Chegg
1 answer:
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Answer:
The value of heat transferred watt per foot length Q = 54.78 Watt per foot length.
Explanation:
Diameter of pipe = 2 in = 0.0508 m
Steam temperature = 300 F = 422.04 K
Duct temperature = 70 F = 294.26 K
Emmisivity of surface 1 = 0.79
Emmisivity of surface 2 = 0.276
Net emmisivity of both surfaces ∈ = 0.25
Stefan volazman constant = 5.67 ×
Heat transfer per foot length is given by
Q = ∈ A (
) ------ (1)
Put all the values in equation (1) , we get
Q = 0.25 × 5.67 × × 3.14 × 0.0508 × 1 × (
)
Q = 54.78 Watt per foot.
This is the value of heat transferred watt per foot length.