Answer:
The distance of the runners from the flag pole is 1.28 miles west of the flagpole
Explanation:
Both the runners will meet at the same time = t
Distance they will cover together = 7 + 1 = 8 miles
Let speed of runner A = v₁ = 5 mph
Let speed of runner B = v₂ = 2 mph
Distance = Speed × Time
v₁t+v₂t = 8
Distance covered by runner A = v₁t = 5× (8/7) = 5.71 miles
Distance of runner A from flagpole = 7-5.71 = 1.28
The distance of the runners from the flag pole is 1.28 miles west of the flagpole.
Answer:
Both balls hit the ground simultaneously
Explanation:
Let´s call b₁ ( the ball dropped ) the equation for a free fall movement is, tacking as the origin of coordinates the level from which it was dropped
V = g*t ( since V₀ initial velocity is 0 )
In the case of projectile movement the equation for Vx and Vy (these speeds are independent)
are:
Vx = V₀x (constant) and Vy = Voy + g*t
Vy = V₀ * sin 0⁰ + g*t Vy = 0 + g*t
As we can see V is the same in both cases then the balls hit the ground simultaneously
Mass of 25 kg weight is 25/9.81 slug of mass.
Answer:
I would say the answer is the wave of 21.000Hz
Explanation:
Because it has more frequency, and as more frequency you add, the time or longer period also increases.