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Eva8 [605]
3 years ago
14

How many moles of hypomanganous acid, H3MnO4, are contained in 22.912 g?

Chemistry
1 answer:
harkovskaia [24]3 years ago
4 0

Answer:

0.188mol

Explanation:

Using the formula as follows:

mole = mass/molar mass

Molar mass of hypomanganous acid, H3MnO4 = 1(3) + 55 + 16(4)

= 3 + 55 + 64

= 122g/mol

Mass of H3MnO4 is given as 22.912 g

Hence;

moles = 22.912 ÷ 122

number of moles = 0.188mol

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What is the limiting reactant when 5.6 moles of aluminum react with 6.2 moles of water?
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7 0
3 years ago
Read 2 more answers
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