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Naily [24]
3 years ago
12

A side reaction occurs when acid is added to the system. which species reacts with the acid?

Chemistry
1 answer:
Phantasy [73]3 years ago
8 0
The reaction is a base
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Answer:

A

Explanation:

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1. Which statement describes the properties of both elements that have just one valence electron and elements that have seven va
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You are given a silver rod, copper plate and copper sulphate solution. Explain the arrangements you will do to get coating of co
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<u>U</u> <u>VORBELLO</u> <u>FRANÇAIS</u><u>?</u><u>?</u><u>?</u>

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3 years ago
When magnesium reacts with hydrochloric acid, hydrogen gas is formed: 2HCl + Mg → H2 + MgCl2. What is the volume of hydrogen pro
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Answer:- C. 16.4 L

Solution:- The given balanced equation is:

2HCl+Mg\rightarrow H_2+MgCl_2

From this equation, there is 2:1 mol ratio between HCl and hydrogen gas. First of all we calculate the moles of hydrogen gas from given grams of HCl using stoichiometry and then the volume of hydrogen gas could be calculated using ideal gas law equation, PV = nRT.

Molar mass of HCl = 1.008 + 35.45 = 36.458 gram per mol

The calculations are shown below:

49.0gHCl(\frac{1molHCl}{36.458gHCl})(\frac{1molH_2}{2molHCl})

= 0.672molH_2

Now we will use ideal gas equation to calculate the volume.

n = 0.672 mol

T = 25 + 273 = 298 K

P = 101.3 kPa = 1 atm

R = 0.0821\frac{atm.L}{mol.K}

PV = nRT

1(V) = (0.672)(0.0821)(298)

V = 16.4 L

From calculations, 16.4 L of hydrogen gas are formed and so the correct choice is C.

7 0
3 years ago
A sample of krypton gas with a volume of 10.00 L has a temp of 303 K and exerts
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<u>Answer:</u> The final volume will be 14.85 L.

<u>Explanation:</u>

To calculate the final volume when temperature increases, we use Charles' Law.

This law states that volume is directly proportional to the temperature of the gas if number of moles and pressure remains constant.

V\propto T\\\\\frac{V_1}{T_1}=\frac{V_2}{T_2}

where,

V_1\text{ and }T_1 = Initial volume and temperature

V_2\text{ and }T_2 = Final volume and temperature

We are given:

V_1=10L\\&#10;T_1=303K\\&#10;V_2=?L\\&#10;T_2=450K

Putting values in above equation, we get:

\frac{10L}{303K}=\frac{V_2}{450K}

V_2=14.85L

Hence, the final volume of the gas is 14.85L

7 0
3 years ago
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