So you find the moles of the lead nitrate by doing mass/Mr so 25/331.2 which gives you 0.075
Due to stoichiometry in the reaction we see 1:2 ratio so we do 0.075x2 gives 0.15 moles of NaNO3
Then mass: moles x Mr so 0.15 x 85= 12.75g is your theoretical
So % yield is actual/ theoretical x 100
Therefore 6.0g/12.75 g x 100 = 47%
Not sure if it’s correct hope it helps!
Answer:
Pyridine
Explanation:
Pyridine is a stronger nucleophile than pyrole ,
Since , both have a lone pair of electron on its nitrogen atom , and both the structure are aromatic in nature .
But , in case of pyrole , the lone pair on nitrogen participates in the delocalization and makes the ring aromatic in nature . hence the lone pair losses its nuleophilic character .
But , in case of pyridine , the lone are free to act as a nucleophile , since they are not involved in the delocalization of the ring .
You need to find which intermolecular forces are between the molecules
dipole-dipole,h bonds, etc.
I'm not very good at explaining but this is what my prof said to help us
Identify the class of the molecule or molecules you are given. Are they nonpolar species, ions or
do they have permanent dipoles? Is there only one species or are there two?
In the case of ONE species (i.e., a pure substance), the intermolecular forces will be between
molecules of the same type. So if you are dealing with ions, the intermolecular forces will be ION-
ION or IONIC. If you are dealing with dipoles, then the intermolecular forces will be DIPOLE-
DIPOLE. If you are dealing with nonpolar species, the intermolecular forces will be DISPERSION
or VAN DER WAALS or INDUCED DIPOLE-INDUCED DIPOLE (the last three are desciptions
of the same interaction; regrettably we cannot call them nonpolar-nonpolar!).
In the case of TWO species (i.e., a mixture), the intermolecular forces will be between molecules of
one type with molecules of the second type. For example, ION-DIPOLE interactions exist between
ions dissolved in a dipolar fluid such as water.