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Trava [24]
3 years ago
12

Which equation in point slope form is shown in the graph below

Mathematics
1 answer:
oee [108]3 years ago
3 0

Answer:

D

Step-by-step explanation:

I know that its correct because I got it correct

it should equal to y=-2/7x+13/7

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Which equation has a solution of n = 4?
Allushta [10]

Answer:

D. 7n = 28

Step-by-step explanation:

Let's substitute 4 for n in each equation to check if it the resulting equation is correct:

6+n=24\\ 6+4=24\\ 10\neq 24\rightarrow \text{Incorrect!}

5n=54\\5(4)=54\\20\neq54\rightarrow\text{Incorrect!}

12-n=16\\12-4=16\\8\neq16\rightarrow\text{Incorrect!}

7n=28\\7(4)=28\\28=28\rightarrow\text{Correct!}

Therefore the answer is D

4 0
2 years ago
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Can someone help me with these questions
Luda [366]
The worksheet pic is not clear
4 0
4 years ago
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What is an algebraic equation for four times a number y is sixteen
Len [333]

4y=16

y is the variable. If you were to solve the equation you would write the equation as 4(4)=16.

3 0
4 years ago
Which triangle is it ?
coldgirl [10]
The answer is: The first triangle. The reasons are shown below:

 1. All the triangles are rigth triangles, because they have an angle of 90°. So, let's calculate the others angles of the first one:

 Tan(α)^-1= opposite leg/adjacent leg

 Opposite leg=5
 Adjacent leg=5√3

 Tan(α)^-1= 5/5√3
 Tan(α)^-1=30°

 2. Let's calculate the other angle:

 Tan(α)^-1= opposite leg/adjacent leg

 Now, the opposite leg will be 5√3 and the adjacent leg will be 5. Then:

 Tan(α)^-1= 5√3/5
 Tan(α)^-1=60°

 As you can see, the angles of first triangle are: 30°,60° and 90°. 
5 0
3 years ago
A paperweight is shaped like a triangular pyramid. The base is an equilateral triangle. Find the surface area of the paperweight
stich3 [128]

Answer:

The surface area of the paperweight is SA=8.3\ in^2

Step-by-step explanation:

we know that

The surface area of the triangular prism is equal to the area of its triangular base plus the area of its three triangular lateral faces

so

<em>Find the area of its triangular base</em>

SA=\frac{1}{2}(2)(1.7)

SA=1.7\ in^2

<em>Find the area of its three triangular lateral faces</em>

SA=3[\frac{1}{2}(2)(2.2)]

SA=6.6\ in^2

Adds the areas

SA=1.7+6.6

SA=8.3\ in^2

4 0
4 years ago
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