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denis23 [38]
3 years ago
14

Two boulders have masses of 7.5 x 106 kg and 9.2 x 105 kg. After rolling apart, their centers are separated by a distance of 124

m. Find the gravitational attraction FG between them.
Physics
1 answer:
aleksley [76]3 years ago
4 0

Answer:

0.0299 N

Explanation:

Applying,

F = Gmm'/r²................... Equation 1

Where F = gravitational force between the boulders, m = mass of the first boulder, m' = mass of the second boulder, r = distance between the boulders, G = Universal constant.

From the question,

Given: m = 7.5×10⁶ kg, m' = 9.2×10⁵ kg, r = 124 m

Constant: G = 6.67×10⁻¹¹ Nm²/kg²

Substitute these values into equation 1

F = (6.67×10⁻¹¹× 7.5×10⁶ × 9.2×10⁵ )/124²

F = (460.23)/15376

F = 0.0299 N

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Answer:

Explanation:

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When we apply  a greater force on it it starts moving with acceleration .

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3 years ago
Two pipes move the same amount of ideal fluid in the same amount of time. One pipe has a 2 in. diameter; the other has a 3 in. d
KATRIN_1 [288]

Answer:

a) 3-in. pipe

Explanation:

Given that

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Volume flow rate

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A=\dfrac{\pi}{4}d^2

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That is why the 3 in diameter is having more pressure than 2 in diameter pipe.

Therefore the answer will be a.

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3 years ago
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In this part of the problem, the reference point is the ceiling. So, the ball is located 2.16 m below the ceiling: therefore, the heigth is

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In this part of the problem, the reference point is the floor.

The height of the ball relative to the floor is equal to the height of the floor minus the length of the string:

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3. 0 J

As before, the gravitational potential energy of the ball is given by

U=mgh

Here the reference point is a point at the same elevation of the ball.

This means that the heigth of the ball relative to that point is zero:

h = 0 m

And so the gravitational potential energy is

U=(1.1 kg)(9.8 m/s^2)(0 m)=0 J

4 0
3 years ago
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