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3 years ago

HNJTYNTYHYHGYHY6HYHY5HTH

Physics

2 answers:

amm18123 years ago

5 0

Answer:

???

Explanation:

Ipatiy [6.2K]3 years ago

3 0

Answer:

Explanation:

fvtgyn

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A 60.kg giri roils down a frictionless hill on a skateboard. At the bottom of the hill, she is traveling at a speed of 30. m/s.

belka [17]

Answer:

She won't have any kenetic energy at the bottom of the hill

Explanation:

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3 years ago

A piece of plastic has a net charge of +9.9 μC. How many more protons than electrons does this piece of plastic have? (e = 1.60

Leto [7]

Answer:

The number of protons 6.19 more than electron.

Explanation:

Given that,

Charge $Q=+9.9\times10^{-6}\ C$

We know that,

formula of charge

$Q = nc$

Where,

Q = total charge

n = number of protons

e = charge of electron

Put the value into the formula

$n = \dfrac{Q}{e}$

$n=\dfrac{9.9\times10^{-6}}{1.6\times10^{-19}}$

$n=6.1875\times10^{13}\ C$

According to statement of question

Divide the answer by $10^{13}$

$n=\dfrac{6.1875\times10^{13}}{10^{13}}$

$n=6.19\ C$

Hence, The number of protons 6.19 more than electron.

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3 years ago

When water vapor is cooled it three forms into water droplets why does this represent a conservation in mass

AVprozaik [17]

In the conservation of mass, mass is never created or destroyed in chemical reactions in the same way water is not created or destroyed it is only transferred from one form to another and its mass is always conserved.

8 0

3 years ago

Identify the names, charges, and location of three types of subatomic particles that make up an atom.

Eva8 [605]

Answer:Proton (charge of +e, in the nucleus), Neutron (0 charge, in the nucleus), and Electron (charge of –e, outside the nucleus).Nov 13, 2015

Explanation: YA

3 0

2 years ago

Read 2 more answers

Determine the volume displaced and then calculate the density of this 54 g sample of brass.

inessss [21]

Answer:

DETAILS IN THE QUESTION INSUFFICIENT TO ANSWER

Explanation:

Assuming the liquid to be water ,

the density $d_{w}$ of water is : $1000kgm^{-3}=1gcm^{-3}$

Buoyant force exerted by a liquid on an object with $V_{imm}$ of it's volume immersed is :

$F_{B}=V_{imm}*d_{l}*g$

where ,

$F_{B}$ is the buoyant force
$d_{l}$ is the density of the liquid
$g$ is the acceleration due to gravity

Thus at equilibrium:

$m_{brass}*g=V_{imm}*d_{l}*g\\m_{brass}=V_{imm}*d_{l}\\54=V_{imm}*1\\V_{imm}=54cm^{3}$

from these , we get the density of brass to be $1gcm^{-3}$

which is not possible

7 0

3 years ago