Answer:
The acceleration of the woman is 0.44 m/s²
Explanation:
Given;
mass of the woman, m₁ = 90 kg
mass of the boy, m₂ = 60 kg
The force applied by the boy, f₂ = 40 N
The net horizontal force on the woman = 40 N
Apply Newton's second law of motion to determine the acceleration of the woman;
f = ma
a = f / m
a = 40 / 90
a = 0.44 m/s²
Therefore, the acceleration of the woman is 0.44 m/s²
The leaf fell at the crooked path instead of straight down because air currents and gravity applied changing and unbalanced forces to the leaf.
<h3>What is an air current?</h3>
An air current is defined as the changes in atmospheric pressure that causes the movement of air from one area to another.
When a leaf is detached naturally from the tree, it won't fall straight down to the floor but will fall a distance away from the tree due to the action of air current and some unbalanced forces.
Learn more about leaf here:
brainly.com/question/24234175
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Answer:
See attached picture.
Explanation:
See attached picture for explanation.
Answer: h = 0.52m
Explanation:
Using the equation of out flow;
A1 × V1 = A2 ×V2
Where A1 = area of the first nozzle
A2 = area of the second nozzle
V1= velocity of flow out from the first nozzle
V2 = velocity of flow out from 2nd nozzle
But AV= area of nozzle × velocity of water = volume of water per second(m³/s).
Now we can set A×V = Area of nozzle × height of rise.
Henceb A1× h1 = A2 × h2 ( note the time cancel on both sides)
D1 = 20mm= 0.02m; h1 = 0.13m
D2 = 10mm = 0.01m; h2= ?
h2 = π(D1/2)²× h1 /π(D2/2)²
h2 = (0.02/2)² × 0.13/(0.01/2)²
= (0.01)² ×0.13 /(0.005)²
= 1.3 × 10^-5/(5 × 10^-3)²
= 1.3 × 10^-5/25 × 10^-6
= (1.3/25) 10^-5 × 10^6
= 0.052× 10
= 0.52m
Its acceleration is constant.
