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Dafna11 [192]
3 years ago
13

Help ASAP!!!!!!!!!!!!!!!!!​

Mathematics
2 answers:
Karolina [17]3 years ago
7 0

Answer:158 centimeters

Step-by-step explanation:7/10 in centimeters is 70 cm and 1/2 meter in centimeters is 50 so, 38+70+50=158cm

polet [3.4K]3 years ago
6 0

Answer:

158cm

Step-by-step explanation:

7/10+1/2 = ? 7/10+5/10=12/10=1 2/20

1 2/10+38cm =120cm+38 cm= 158

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The graph of F(x) shown below resembles the graph of G(x) = x4, but it has
DerKrebs [107]

Using translation concepts, the equation of F(x) is:

A. F(x) = \frac{1}{3}x^4 - 2

<h3>What is a translation?</h3>

A translation is represented by a change in the function graph, according to operations such as multiplication or sum/subtraction in it's definition.

The parent function is:

G(x) = x^4

For function F(x), we have that:

  • It was shifted down 2 units, hence F(x) = G(x) - 2.
  • It was vertically compressed by a factor of 3, hence F(x) = \frac{1}{3}G(x) - 2

Then the equation is:

A. F(x) = \frac{1}{3}x^4 - 2

More can be learned about translation concepts at brainly.com/question/28098112

#SPJ1

3 0
2 years ago
Amy has a piece of wood that measures 42 inches. The model shows the length remaining after she cut a piece from the 42-inch pie
Hitman42 [59]

Answer:

She has 42 pieces of wood each of 1 inch of length.

Step-by-step explanation:

Amy has 42 inches piece of wood.

She has to cut an inch.

After cutting pieces of inch each she counts the pieces to be 42.

Mathematically

Total length / unit lenght = Number of pieces

42 inches/ 1 inch= 42 pieces.

She has 42 pieces of wood each of 1 inch of length.

6 0
3 years ago
Help me i need to submit to my teacher by 8pm​
Vladimir [108]

Please see the figure. We'll first work out half the area of the rounded triangle, half the unshaded part, then double it, then subtract it from the big square.

Half the area is the circular sector PTQ (with center P, arc TQ) minus the right triangle PUT.

A/2 = area(sector PTQ) - area(triangle PUT)

The triangle is half of equilateral triangle PQT, so a 30/60/90 right triangle so we know the sides are in ratio 1:√3:2 so

TU = (7/2)√3

area(PUT) = (1/2) (7/2)(7/2)√3 = (49/8)√3

area(sector PTQ) = (angle TQP / 360°) πr^2

We know angle TQP is 60° because TQP is equilateral.  r=7.

area(sector PTQ) = (60°/360°) π (7²) = 49π/6

Putting it together,

A/2 = area(sector PTQ) - area(triangle PUT)

A = 2(49π/6 -  (49/8)√3)

A = 49(π/3 - √3/4) square cm

I hate ruining a nice exact answer with an approximation, but they seem to be asking.

A ≈ 30.095057615914535

Check:

I'm not sure how to check it.  I'd estimate it's about 25% bigger than equilateral triangle PQT with area (√3/4)7² ≈ 21.2, so around 27. 30 seems reasonable.

Now the real area we seek is the big square PQRS minus A, so

area = 7² - 30.095057615914535 = 18.904942384086 sq cm

They want square meters for some reason; we scale by (1/100)²

Answer: 0.00189 square meters

7 0
3 years ago
Genesis would like to join a Book Club. She needs to pay $12.00 for entrance into the book
77julia77 [94]

Answer:

An equation in function notation for the total cost of the book  club will be:

  • y = 20x + 12

Step-by-step explanation:

Given that Genesis needs to pay $12.00 for entrance into the book club.

Per month fee = $20.00

We know that the slope-intercept form of a linear function is

y = mx+b

where m is the slope and b is the y-intercept

As the rate of change is also called the slope.

The rate of $20.00 per month would be termed as the slope = m = 20

One time fee = $12.00, meaning the y-intercept = b = 12

Thus, the equation becomes

y = mx+b

  • y represents the total cost
  • x represents the duration
  • m represents the rate of change = m = 20
  • b represents the y-intercept = b = 12

y = 20x + 12

Therefore, an equation in function notation for the total cost of the book  club will be:

  • y = 20x + 12
5 0
3 years ago
If An=An−1 + 4 and A5 = 12, what is A7?
dangina [55]

Answer:

The frequency of A7, which is two octaves above A5, is 3520 (880 x 2 x 2) Hz. The octave term is used in the musical composition to relate the same notes in the higher or lower scale of notes. The note in the one octave higher scale have a doubled frequency than in the neutral scale and The note in the one octave lower scale have a half frequency than in the neutral scale.

Step-by-step explanation:

MARK BRAINLIEST PLEASE!!!!!!!

3 0
3 years ago
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