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exis [7]
3 years ago
8

Convert 0.00378 kg into grams

Chemistry
2 answers:
RideAnS [48]3 years ago
8 0

Answer:    3.78 grams

Hoped I helped -

Sleepy~

Lelu [443]3 years ago
6 0

Answer:

3.78

Explanation:

i'm smart

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g The combustion of 1.877 1.877 g of glucose, C 6 H 12 O 6 ( s ) C6H12O6(s), in a bomb calorimeter with a heat capacity of 4.30
Mekhanik [1.2K]

Answer:

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Explanation:

According to the law of conservation of energy, the sum of the heat absorbed by the bomb calorimeter (Qcal) and the heat released by the combustion of the glucose (Qcomb) is zero.

Qcal + Qcomb = 0

Qcomb = - Qcal [1]

We can calculate the heat absorbed by the bomb calorimeter using the following expression.

Qcal = C × ΔT = 4.30 kJ/°C × (29.51°C - 22.71°C) = 29.2 kJ

where,

C: heat capacity of the calorimeter

ΔT: change in the temperature

From [1],

Qcomb = - Qcal = -29.2 kJ

The internal energy change (ΔU), for the combustion of 1.877 g of glucose (MW 180.16 g/mol) is:

ΔU = -29.2 kJ/1.877 g × 180.16 g/mol = -2.80 × 10³ kJ/mol

3 0
4 years ago
What's the molality of a solution with 120 g of NaCl and 30 kg of water?
hodyreva [135]

Answer:

B

Explanation:

120÷30kg

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hope it helps

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3 years ago
Which of the following elements have seven valance electrons in its outer shell?
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4 years ago
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