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koban [17]
3 years ago
7

The reaction A + 2B + C -- >D + 2E is first order in reactant A, first order in B, and second order in C. What is the rate la

w equation for this reaction?
A) rate = [A][B]2[C]
B) rate = [A][B][C]2
C) rate = [A][B]/2[C]
D) rate = k[A][B][C]2
E) k = [A][B][C]2
Chemistry
2 answers:
kvasek [131]3 years ago
7 0
The answer should be D.  A rate law needs to be rate equaling the rate constant which is represented as k (make sure you use a lower case k since an upper case K is for equilibrium) times the concentrations of each reactant raised to the power of what ever order it has. (if A was a zero order it would be [A]⁰ and if A was third order it would be [A]³).
Do not get the order the reactants are confused with the coefficients in the chemical equation. (just because the reaction has 2B does not mean the rate law will have [B]².  As shown in this example since it is first order therefore being [B] in the rate law)

I hope this helps. Let me know if anything is unclear in the comments.
miskamm [114]3 years ago
5 0

Answer : The correct option is, (B) \text{Rate}=k[A][B][C]^2

Explanation :

Rate law : It is defined as the expression which expresses the rate of the reaction in terms of molar concentration of the reactants with each term raised to the power their stoichiometric coefficient of that reactant in the balanced chemical equation.

The general reaction is:

A+B\rightarrow C+D

The general rate law expression for the reaction is:

\text{Rate}=k[A]^a[B]^b

where,

a = order with respect to A

b = order with respect to B

R = rate  law

k = rate constant

[A] and [B] = concentration of A and B reactant

Now we have to determine the rate law for the given reaction.

The balanced equations will be:

A+2B+C\rightarrow D+2E

In this reaction, A, B and C are the reactants and the 1st order of reaction for reactant A, 1st order of reaction for reactant B and 2nd order of reaction for reactant C.

The rate law expression for the reaction will be:

\text{Rate}=k[A]^1[B]^1[C]^2

or,

\text{Rate}=k[A][B][C]^2

Hence, the correct option is, (B) \text{Rate}=k[A][B][C]^2

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The correct answer to thi
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3 years ago
23 grams of sodium reacts with 293 cm 3 of water that is initially at 298 k. it produces an enthalpy change of 197 kj. what is t
m_a_m_a [10]

448 K is the final temperature of the water.

<h3>What is specific heat capacity?</h3>

The specific heat capacity is defined as the quantity of heat (J) absorbed per unit mass (kg) of the material when its temperature increases by 1 K (or 1 °C), and its units are J/(kg K) or J/(kg °C).

Given,

the mass of Na is 23 g

The volume of water = 293 cm3

Mass of water = 293 g

Total solution mass = 23 g + 293 g = 316 g

Specific heat capacity of water = 4.18 J/Kg

The equation relating mass, heat, specific heat capacity and temperature change is:

q = mcΔT

197 kJ = 316 g x 4.18 J/Kg x (T_{finals} - T_ {initial})

197 kJ = 316 g x 4.18 J/Kg x ( T_{finals}-298 K)

0.1491429956 x 1000 =  T_{finals}-298 K

149.1429956 + 298 = T_{finals}

447.1429956 = T_{finals}

448 K = T_{finals}

Hence, 448 K is the final temperature of the water.

<h3>What does a high specific heat capacity mean?</h3>

A high specific heat capacity means that it can store a large amount of thermal energy for a small change in mass or temperature.

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2 years ago
You want to place a piece of glass tubing into a ruber stopper after the tubing has been fire polished and cooled. This is best
igor_vitrenko [27]

Answer:

All of the above

Explanation:

This is correct

4 0
3 years ago
Given that ΔH = −571.6 kJ/mol for the reaction 2 H2(g) + O2(g) → 2 H2O(l), calculate ΔH for these reactions. (a) 2 H2O(l) → 2 H2
pashok25 [27]

Answer : The value of \Delta H for the reaction is +571.6 kJ/mole.

Explanation :

According to Hess’s law of constant heat summation, the heat absorbed or evolved in a given chemical equation is the same whether the process occurs in one step or several steps.

According to this law, the chemical equation can be treated as ordinary algebraic expression and can be added or subtracted to yield the required equation. That means the enthalpy change of the overall reaction is the sum of the enthalpy changes of the intermediate reactions.

The given chemical reaction is,

2H_2(g)+O_2(g)\rightarrow 2H_2O(l)     \Delta H_1=-571.6kJ/mole

Now we have to determine the value of \Delta H for the following reaction i.e,

2H_2O(l)\rightarrow 2H_2(g)+O_2(g)    \Delta H_2=?

According to the Hess’s law, if we reverse the reaction then the sign of \Delta H change.

So, the value \Delta H_2 for the reaction will be:

\Delta H_2=-(-571.6kJ/mole)

\Delta H_2=+571.6kJ/mole

Hence, the value of \Delta H for the reaction is +571.6 kJ/mole.

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3 years ago
What is the mass of 1.72 moles of sodium nitrate? Use the periodic table and the polyatomic ion resource. A. 85.0 g B. 91.2 g C.
Mrac [35]
The answer is C. 146g because you add all of the masses of the individual elements and then mulyiply by 1.72 to get your answer.
7 0
3 years ago
Read 2 more answers
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