Review the function table below. Enter the slope of the function in the box.

Hadley has 3/6 of a box of white envelopes and 1/3 of a box of gray envelopes. When full, each box of envelopes has the same num

QveST [7]

Answer:

<u>The two statements that apply are A and B.</u>

Step-by-step explanation:

1. Let's review the information given to us to answer the question correctly:

White envelopes Hadley has = 3/6 of a box

Gray envelopes Hadley has = 1/3 of a box

When full, each box of envelopes has the same number of envelopes

Hadley said she has 4/9 of a box when she puts the white envelopes and gray envelopes together.

2. Which statements describe this situation? Select the two statements that apply.

Let's add 3/6 and 1/3

3/6 + 1/3 = 3/6 + 2/6 = 5/6

A. Hadley’s answer is incorrect, because 3/6 is equal to 1/2 , and 4/9 is less then 1/2 . This is correct.

B. Hadley's answer is incorrect, because 3/6 plus 1/3 equals 5/6. This is correct.

C. Hadley's answer is incorrect, because 3/6 plus 1/3 equals 2/6. This is wrong

D. Hadley's answer is correct, because 3 and 1 is 4, and 6 and 3 is 9. This is wrong.

<u>The two statements that apply are A and B.</u>

3 0

3 years ago

Four students took a national standardized test for which the mean was 500 and the standard deviation was 100. If a student’s z-

murzikaleks [220]

z = (x - 500) / 100

1.75 = (x - 500) / 100

175 = x - 500

675 = x

3 0

4 years ago

Read 2 more answers

Ariana's grandfather made a scaled down model of a knitting needle to be placed inside a dollhouse. Arianna measured the model b

Andrew [12]

Answer:

10.5

Step-by-step explanation:

1.5 inches

.5 and 1.5 =3

3x3.5=10.5

3 0

3 years ago

Read 2 more answers

Question Help Suppose that the lifetimes of light bulbs are approximately normally distributed, with a mean of 5656 hours and a

koban [17]

Answer:

a)3.438% of the light bulbs will last more than 6262 hours.

b)11.31% of the light bulbs will last 5252 hours or less.

c) 23.655% of the light bulbs are going to last between 5858 and 6262 hours.

d) 0.12% of the light bulbs will last 4646 hours or less.

Step-by-step explanation:

Normally distributed problems can be solved by the z-score formula:

On a normaly distributed set with mean $\mu$ and standard deviation $\sigma$ , the z-score of a value X is given by:

$Z = \frac{X - \mu}{\sigma}$

After we find the value of Z, we look into the z-score table and find the equivalent p-value of this score. This is the probability that a score will be LOWER than the value of X.

In this problem, we have that:

The lifetimes of light bulbs are approximately normally distributed, with a mean of 5656 hours and a standard deviation of 333.3 hours.

So $\mu = 5656, \sigma = 333.3$

(a) What proportion of light bulbs will last more than 6262 hours?

The pvalue of the z-score of $X = 6262$ is the proportion of light bulbs that will last less than 6262. Subtracting 100% by this value, we find the proportion of light bulbs that will last more than 6262 hours.