Answer:
iv. The motion between A & B moves at a further distance than C & D's
v. The cyclist travels 800 meters
vi. It takes approx. 80 seconds
vii. The cyclist's speed is 10 meters per second (m/s)
viii. The cyclist's speed is also 10 meters per second (m/s)
vii. (2) The cyclist's average speed is 10 meters per second (m/s)
Explanation:
Speed is calculated using the formula distance divided by time (d/t)
vii (2) needs further explanation:
Though there is a moment of rest, the cyclist still travels the same speed throughout the entire trip. To check this answer however, you can total the distance and time the cyclist traveled and use speed formula to get 10 meters per second, again.
Preparing 15 mg/gl working standard solution from a 20 mg/dl stock solution will require the application of the dilution principle.
Recalling the principle:
initial volume x initial molarity = final volume x final molarity
Since we were not given any volume to work with, we can as well just take an arbitrary volume to be prepared. Let's assume that the stock solution is 10 mL and we want to prepare 15 mg/gl from it:
Applying the dilution principle:
10 x 20 = final volume x 15
final volume = 200/15
= 13.33 mL
This means that in order to prepare 13.33 mL, 15 mg/l working standard solution from 10 ml, 20 mg/dl stock solution, 3.33 mL of the diluent must be added to the stock solution.
More on dilution principle can be found here: brainly.com/question/11493179
Answer:
Explanation:
Double displacement reaction is a type of reaction in which two compounds react by exchanging ions to form two new compounds.It is represented by the equation below.
AB +CD=AD + CB
Answer:
B
Explanation:
Please take a look at the picture attached for the drawings and structures.
C2H4 is a alkene (C-C double bond). When steam (water) is added, it turns into an alcohol, where the double bond breaks and a (-OH) functional group is attached to one of the Carbons. In this case, C2H4 ethene is turned into ethanol.
When an alcohol undergoes oxidation, primary alcohols turn into aldehyde (-CHO) or carboxylic acids (-COOH). Secondary alcohol turns into ketone. Ethanol is a primary alcohol. And since it later reacts with propanol, it can only form carboxylic acid when it oxidizes. The product in this reaction is ethanoic acid.
Carboxylic acid reacts with alcohol to form an ester (-COO-). the -COOH group from acid combines with the -OH group from alcohol to form an ester bond -COO- while eliminating H2O. Therefore, when propanol undergoes esterification with ethanoic acid, propyl ethanoate is produced. It is the answer of B.
