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4 years ago

I need a help from this question!!

Chemistry

1 answer:

Alik [6]4 years ago

7 0

Answer:

Explanation:

Please take a look at the picture attached for the drawings and structures.

C2H4 is a alkene (C-C double bond). When steam (water) is added, it turns into an alcohol, where the double bond breaks and a (-OH) functional group is attached to one of the Carbons. In this case, C2H4 ethene is turned into ethanol.

When an alcohol undergoes oxidation, primary alcohols turn into aldehyde (-CHO) or carboxylic acids (-COOH). Secondary alcohol turns into ketone. Ethanol is a primary alcohol. And since it later reacts with propanol, it can only form carboxylic acid when it oxidizes. The product in this reaction is ethanoic acid.

Carboxylic acid reacts with alcohol to form an ester (-COO-). the -COOH group from acid combines with the -OH group from alcohol to form an ester bond -COO- while eliminating H2O. Therefore, when propanol undergoes esterification with ethanoic acid, propyl ethanoate is produced. It is the answer of B.

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3 years ago

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A marine biologist is preparing a deep-sea submersible for a dive. The sub stores breathing air under high pressure in a spheric

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Complete Question

A marine biologist is preparing a deep-sea submersible for a dive. The sub stores breathing air under high pressure in a spherical air tank that measures 74.0 wide. The biologist estimates she will need 2600 L of air for the dive. Calculate the pressure to which this volume of air must be compressed in order to fit into the air tank. Write your answer in atmospheres. Round your answer to significant digits.

Answer:

The pressure required is $P_2= 12.2 \ atm$

Explanation:

Generally the volume of a sphere is mathematically denoted as

$V_s = \frac{4}{3} * \pi r^3$

Substituting $r = \frac{d}{2} = \frac{74}{2} = 37cm$

$V_s = \frac{4}{3} * 3.42 * (37)^2$

$V_s = 2.121746 *10^5 cm^3$

Converting to Liters

$V_s = \frac{2.121746 *10^5}{1000}$

$V_s= 212.1746L$

Assume that the pressure at which the air is given to the diver is 1 atm when the air was occupying a volume of 2600L

From Charles law

$P_1V_1 = P_2 V_s$

Substituting $V_1 =2600 L$ , $P_1 = 1 atm$ , $V_s =212.1746L$ , and making $P_2$ the subject we have

$P_2 = \frac{P_1 * V_1}{V_s}$

$= \frac{1 * 2600}{212.1746}$

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3 years ago

A 220.0-mL sample of helium gas is in a cylinder with a movable piston at 105 kPa and 275K. the piston is pushed until the sampl

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Using the general gas equation:

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(105*220)/275 = (P₂*95)/310

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4 years ago

In a given population, which members are most likely to survive and produce offspring?

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Answer:

Those individuals with advantageous traits are more likely to survive and reproduce. The survivors pass down these advantageous traits to their offspring.

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3 years ago

For which of the following reactions is S° > 0.

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The entropy of the given reactions increases (S° > 0):

2C2H6(g) + 7O2(g) ----> 4CO2(g) + 6H2O(g) ---> S° > 0.
NH4Cl(s) ----> NH3(g) + HCl(g) ---> S° > 0.

<h3>What is entropy?</h3>

Entropy measure how disordered a system is. It a measure of how dispersed or random the total energy of a system is. The symbol for entropy is S.

A system in which entropy increases is one in which S° > 0.

The entropy of a system decreases when S° < 0.

Entropy of a system increases (S° > 0) if any change results in an increase in temperature, increase in number of molecules, or an increase in volume.

Considering the given systems, the entropy changes is as follows:

2C2H6(g) + 7O2(g) ----> 4CO2(g) + 6H2O(g) ---> S° > 0.
2CO2(g) + N2(g) ---->2CO(g) + 2NO(g) --> no change
2N2(g) + O2(g) -----> 2N2O(g) ---> decreases
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NH4Cl(s) ----> NH3(g) + HCl(g) ---> S° > 0.

In conclusion, an increase in volume and moles of substances results in entropy increase.

Learn more about entropy at: brainly.com/question/26691503

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2 years ago