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PtichkaEL [24]
3 years ago
8

Show, in a step by step fashion, your calculations to determine the percent

Chemistry
1 answer:
marusya05 [52]3 years ago
8 0

The percent  by volume of a solution : 19.23%

<h3>Further explanation</h3>

Given

50 ml of ethanol

210  ml of water

Required

The percent  by volume of a solution

Solution

Percent Volume (% v/v) : volume (ml) of solute/100 ml of solution ⇒ ratio of the volume of the solute to total volume of the solution

\tt \%solute(v/v)=\dfrac{solute~volume}{solution~volume}\times 100\%

solute= Ethanol

solvent=water

Solution = solute+solvent

Total volume of the solution :

\tt =volume~of~Ethanol+solume~of~water\\\\=50~ml+210~ml\\\\=260~ml

Percent by volume :

\tt \%volume=\dfrac{50}{260}\times 100\%\\\\\%volume=19.23\%

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Which type of heat transfer does the situation below model? At a sports event, the spectators do the 'wave'. Starting at one end
Zanzabum

Answer:

radiation

Explanation:

Based on the scenario being described in the question it can be said that the type of heat transfer that is being modeled is radiation. Like demonstrated in the picture attached below, radiation involved the transfer of heat through rays, waves, or particles as opposed to fluids or gases. Which is what is happening in this scenario, since the individuals are building up heat by moving and that heat is being passed on to the individuals around them through waves.

7 0
3 years ago
Urea (CH4N2O) is a common fertilizer that can be synthesized by the reaction of ammonia (NH3) with carbon dioxide as follows: 2N
Gnesinka [82]

Answer:

NH3 is the limiting reactant

The theoretical yield is 216.0 kg urea

The % for this reaction is 78.8 %

Explanation:

<u>Step 1:</u> Data given

Mass of ammonia = 122.5 kg

Mass of carbon dioxide = 211.4 kg

Mass of urea produced = 170.3 kg

Molar mass of ammnoia = 17.031 g/mol

Molar mass of carbon dioxide = 44.01 g/mol

Moalr mass of urea = 60.06 g/mol

<u>Step 2:</u> The balanced equation

2NH3(aq) + CO2(aq) --> CH4N2O(aq) + H2O(l)

<u>Step 3:</u> Calculate moles of NH3

Number of moles = mass / Molar mass

Moles NH3 = 122500 grams / 17.031 g/mol

Moles NH3 = 7192.77 moles

<u>Step 4:</u> Calculate moles of CO2

Moles CO2 = 211400 / 44.01 g/mol

Moles CO2 = 4803.45 moles

<u>Step 5</u>: Calculate limiting reactant

For 2 moles NH3 consumed, we need 1 moles of CO2 to produce 1 mole urea and 1 mole H2O

NH3 is the limiting reactant. It will completely be consumed (7192.77 moles).

CO2 is in excess. There will be consumed 7192.77/2 = 3596.4 moles

There will remain 4803.45 - 3596.4 = 1207.05 moles of CO2

<u>Step 6:</u> Calculate moles of urea produced:

For 2 moles NH3 consumed, we need 1 moles of CO2 to produce 1 mole urea and 1 mole H2O

For 7192.77 moles of NH3, we have 3596.4 moles of urea produced

<u>Step 7: </u>Calculate mass of urea

Mass urea = moles urea * molar mass urea

Mass urea = 3596.4 moles * 60.06 g/mol

Mass urea = 216000 grams = 216 kg = theoretical yield

<u>Step 8</u>: Calculate % yield

% yield = (actual yield / theoretical yield)*100%

% yield = (170.3 / 216) *100% = 78.8%

The % for this reaction is 78.8 %

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3 years ago
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Answer:

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<em></em>

6 0
3 years ago
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Answer:

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Gravity is the force that pulls us to the surface of the Earth, keeps the planets in orbit around the Sun and causes the formation of planets, stars and galaxies.

Hope this helped!!!

5 0
2 years ago
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