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irakobra [83]
3 years ago
12

When a molecule is separated into its components parts it form

Chemistry
2 answers:
Scorpion4ik [409]3 years ago
7 0
Atoms, because molecules are a group of two or more atoms stuck together :)
geniusboy [140]3 years ago
5 0
It would probably be B
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"Write the electron Configuration expected for element 113 and the configurations for the two cations it is most likely to form"
arlik [135]

Answer:

Element:

1s²2s²2p⁶3s²3p⁶4s²3d¹⁰4p⁶5s²4d¹⁰5p⁶6s²4f¹⁴5d¹⁰6p⁶7s²5f¹⁴6d¹⁰7p¹

Cations:

1s²2s²2p⁶3s²3p⁶4s²3d¹⁰4p⁶5s²4d¹⁰5p⁶6s²4f¹⁴5d¹⁰6p⁶7s²5f¹⁴6d¹⁰

1s²2s²2p⁶3s²3p⁶4s²3d¹⁰4p⁶5s²4d¹⁰5p⁶6s²4f¹⁴5d¹⁰6p⁶5f¹⁴6d¹⁰

Explanation:

The electron configuration is the distribution of the electrons in the sublevels in order of the crescent energy of them. The crescent energy of the sublevels follows the Linus Pauling's diagram, which is attached below. The sublevel "s" comports until 2 electrons, the sublevel "p" until 6 electrons, the sublevel "d" until 10 electrons, and sublevel "f" until 14 electrons.

So, for the element with an atomic number of 113, the neutral atom will have 113 electrons:

1s²2s²2p⁶3s²3p⁶4s²3d¹⁰4p⁶5s²4d¹⁰5p⁶6s²4f¹⁴5d¹⁰6p⁶7s²5f¹⁴6d¹⁰7p¹

Thus the element is at the 7 period (the highest level), and group 13 (most energic sublevel p with 1 electron), the group of the aluminum. It needs to lose 3 electrons to be stable and follow the octet rule, but the subshells of the last shell are too far away in energetic order, thus, it most probably to lose the electron of 7p and form a monovalent cation, and can lose the two electrons of 7s to form a trivalent cation:

1s²2s²2p⁶3s²3p⁶4s²3d¹⁰4p⁶5s²4d¹⁰5p⁶6s²4f¹⁴5d¹⁰6p⁶7s²5f¹⁴6d¹⁰

1s²2s²2p⁶3s²3p⁶4s²3d¹⁰4p⁶5s²4d¹⁰5p⁶6s²4f¹⁴5d¹⁰6p⁶5f¹⁴6d¹⁰

5 0
3 years ago
HOW do we know about life from before human time?
GenaCL600 [577]

B fossils

hope this helps :)

8 0
3 years ago
During which of the following phases of the moon do we see the left half of the moon as lit?
xxMikexx [17]
During the 3rd quarter
7 0
3 years ago
solid sodium reacts violently with water producing heat, hydrogen gas and sodium hydroxide. How many molecules of hydrogen gas a
Blababa [14]
Molar mass of sodium=23g
2 mole sodium gives 2 g H2
i.e 46g sodium gives 2g H2
so 65.4g will give=2.84g H2
now no. of molecules = 2.8/2*avogadros number
5 0
3 years ago
PLEASE SOMEBODY EXPLAIN THIS :(((
djverab [1.8K]

Answer:

\boxed{ \sf \: R_f  \: value \: of \: sample \: 1 =0.3142}

<h3>Explanation:</h3>

In Analytical Chemistry chromatography is widely used for the separation of samples.

  • In thin layer chromatography, the mixture of components are separated on the basis of their polarity.
  • The solvent solution(mobile phase) that we use are non polar & silica gel( TLC paper made of/stationary phase) are polar.
  • Consider the mixture we have taken consist of two samples having large polar difference.
  • Due to opposite nature of silica gel(polar) & solvent solution (non polar) the movement become easy & due to capillary action solvent solution rise to the top.
  • The mixture of sample we have taken, the sample have less polarity have high peak or they travel more distance than that of more polar sample when they dipped into the solution.

In the given diagram, mixture of 8 samples are separated on the basis of their polarity, the distance travelled by solvent is 35 mm, distance travelled by sample 1 is 11 mm & similarly distance travelled by sample 2,3,4,5,6,7 are 15,31,4,22,25,33 in mm respectively.

Rf Value: Rf value is retention factor which tells about relative absorption of each sample & range of Rf value is 0-1.

Formula to calculate Rf value is

\sf R_f  \: value = \frac{distance \: moved \: by \: sample}{distance \: moved \: by \: solvent}

Now, solving for Rf value of sample 1

<em>Given:</em>

Distance moved by sample 1 = 11 mm

Distance movedby solvent = 35 mm

<em>To find:</em>

Rf value of sample 1 = ?

<em>Solution:</em>

Substituting the given data in above formula,

\small \sf R_f  \: value = \frac{distance \: moved \: by \: sample \: 1}{distance \: moved \: by \: solvent}   \\  \small \sf R_f  \: value =  \cancel\frac{11  \: mm}{35 \:  mm}  = 0.3142

\small \boxed{ \sf \: R_f  \: value \: of \: sample \: 1 =0.3142}

<em><u>Thanks for joining brainly community!</u></em>

4 0
2 years ago
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