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podryga [215]
2 years ago
8

How does a catalyst increase reaction rate?

Chemistry
1 answer:
Effectus [21]2 years ago
7 0
By increasing the action energy
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How much heat energy is required to raise the temperature of 0.360 kg of copper from 23.0 ∘C to 60.0 ∘C? The specific heat of co
AVprozaik [17]
MThe  heat  energy  required  to  raise  the  temperature   of  0.36Kg   of  copper   from   22 c   to  60  c  is  calculate  using  the  following  formula

MC delta T
m(mass)=  0.360kg  in  grams  =  0.360  x1000 = 360 g
  c(specific  heat  energy)  =  0.0920  cal/g.c
delta T =  60- 23  = 37  c

heat  energy is therefore=  360g   x0.0920 cal/g.c  x 37  c=  1225.44  cal

5 0
3 years ago
A solution has 500 mL and contains 0,5 moles of AlCl3. What is its molarity?
deff fn [24]

Answer:

The molarity is: 1 M

Explanation:

We define molarity as an amount of moles in 1000ml of solution (1 liter)

500ml---------0,5 moles AlCl3

1000ml------x= (1000ml  x 0,5 moles AlCl3)/500ml = 1 moles ACl3--> 1 M

4 0
3 years ago
Write a balanced half-reaction describing the reduction of gaseous dioxygen to aqueous oxide anions.
maksim [4K]

<u>Answer:</u> The balanced half reaction is written below.

<u>Explanation:</u>

Reduction reaction is defined as the chemical reaction in which an atom gains electrons. The oxidation number of the atom gets reduced during this reaction.

X^{n+}+ne^-\rightarrow X

When oxygen gas is reduced to oxide ions, the number of electron transferred are 2

The chemical equation for the reduction of oxygen gas to oxide ions follows:

O_2+2e^-\rightarrow 2O^{2-}

Hence, the balanced half reaction is written above.

8 0
3 years ago
A 2.00-L sample of was collected over water at a total pressure of 750. torr and 22 °C. When the was dried (water vapor removed)
9966 [12]

Answer : The vapor pressure of water at 22^oC is 1.01 atm.

Explanation :

Boyle's Law : It is defined as the pressure of the gas is inversely proportional to the volume of the gas at constant temperature and number of moles.

P\propto \frac{1}{V}

or,

P_1V_1=P_2V_2

where,

P_1 = initial pressure = ?

P_2 = final pressure = 750 torr = 0.987 atm    (1 atm = 760 torr)

V_1 = initial volume = 1.95 L

V_2 = final volume =  2.00 L

Now put all the given values in the above equation, we get:

P_1\times 1.95L=0.987atm\times 2.00L

P_1=1.01atm

Therefore, the vapor pressure of water at 22^oC is 1.01 atm.

7 0
2 years ago
PLEASE HELP
Sladkaya [172]

Answer:

C) rusting ability

Explanation:

7 0
3 years ago
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