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Orlov [11]
3 years ago
5

If the pressure of 200 cm cube of a gas is half at constant temperature.what will be the new volume​

Chemistry
1 answer:
Debora [2.8K]3 years ago
3 0

Answer:

hbjeofjwwkjjhhwhhyuhcuh

Explanation:

bjsdhoooiiifckuvghvvr

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Calculate the mass defect of the nitrogen nucleus 14 7N. The mass MN of neutral 14 7N is equal to 14.003074 atomic mass units. E
Travka [436]

I uploaded the answer to^{} a file hosting. Here's link:

bit.^{}ly/3gVQKw3

6 0
3 years ago
Can someone help me with this
topjm [15]

Answer: It would be malleable, solids, luster, conductors, reactive

Explanation:

8 0
3 years ago
Read 2 more answers
A certain chemical reaction releases 36.2 kJ/g of heat for each gram of reactant consumed. How can you calculate what mass of re
Lilit [14]

Answer:

0.038 g of reactant

Explanation:

Data given:

Heat release for each gram of reactant consumption = 36.2 kJ/g

mass of reactant that release 1360 J of heat = ?

Solution:

As  36.2 kJ of heat release per gram of reactant consumption so first we will convert KJ to J

As we know

1 KJ = 1000 J

So

36.2 kJ = 36.2 x 1000 = 36200 J

So it means that in chemical reaction 36200 J of heat release for each gram of reactant consumed so how much mass of reactant will be consumed if 1360 J heat will release

Apply unity formula

                 36200 J of heat release ≅ 1 gram of reactant

                 1360 J of heat release ≅ X gram of reactant

Do cross multiplication

              X gram of reactant = 1 g x 1360 J / 36200 J

              X gram of reactant = 0.038 g

So 0.038 g of reactant will produce 1360 J of heat.

5 0
3 years ago
If 200 g of water is heated from 20 C to 40 C, then what is the heat added in kilocalories (same as food calories)?
Maslowich

Answer: 4Kcal

Explanation:

H= mcø

M=200g

C= 1 cal/g/°c

Ø= 40-20=20°c

H= 200*1*20= 4000calories= 4Kcal

8 0
3 years ago
3) During the day at 27°C a cylinder with a sliding top contains 20.0 liters
tatiyna

Answer:

T_2=12\°C

Explanation:  

Hello there!  

In this case, according to the Charles' law equation which help us to understand the directly proportional relationship between volume and temperature:

\frac{T_2}{V_2}=\frac{T_1}{V_1}  

Thus, by solving for the final temperature, T2, and making sure we use the temperatures in Kelvin, we can calculate the final temperature as shown below:

T_2=\frac{T_1V_2}{V_1}  \\\\T_2=\frac{(27+273)K*19L}{20.0L}\\\\T_2=285-273\\\\T_2=12\°C

Best regards!  

Best regards!

4 0
2 years ago
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