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nevsk [136]
3 years ago
11

Calculate the pOH and the pH of a 5.0 x 10-2 M solution of NaOH.

Chemistry
1 answer:
k0ka [10]3 years ago
5 0

Answer:

pOH = 1.3, pH = 12.7

Explanation:

Since NaOH is a strong base, it will completely ionize; further, since it completely ionizes, our hydroxide concentration (a product of the ionization) will be the same as the given concentration of NaOH.

NaOH -> Na⁺ + OH⁻, [OH⁻] = 5.0 x 10^-2 M

pOH is the negative log of the hydroxide concentration, so plug our hydroxide concentration in:

pOH = -log[OH⁻] = -log[5.0 x 10^-2 M] = 1.3

Since pH + pOH = 14, we can plug in pOH and solve for pH:

pH + 1.3 = 14

pH = 14 - 1.3 = 12.7

Thus, our pOH = 1.3 and pH = 12.7.

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AVprozaik [17]

Answer: The pressure of the He is 2.97 atm

Explanation:

According to Dalton's law, the total pressure is the sum of individual pressures.

p_{total}=p_{N_2}+p_{O_2}+p_{He}.

Given : p_{total} =total pressure of gases = 6.50 atm

p_{N_2} = partial pressure of Nitrogen = 1.23 atm

p_{O_2} = partial pressure of oxygen = 2.3 atm

p_{He} = partial pressure of Helium = ?

putting in the values we get:

6.50atm=1.23atm+2.3atm+p_{He}  

p_{He}=2.97atm

The pressure of the He is 2.97 atm

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3 years ago
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3 years ago
The nucleus of a lead atom has a charge of 82 protons what are the drection and magnitude
KATRIN_1 [288]

Answer:

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Explanation:

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Match the following polyatomic lons.<br> (Refer to picture)
olya-2409 [2.1K]

Answer:

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