Answer:
Molarity = 0.08 M
Explanation:
Given data:
Volume of NaOH = 24.11 cm³ (24.11/1000 = 0.0241 L)
Mass of C₈H₅KO₄ = 0.43 g
Molarity of NaOH = ?
Solution:
First of all we will write the chemical equation:
C₈H₅KO₄ + NaOH → H₂O + KNaC₈H₄O₄
Number of moles of C₈H₅KO₄:
Number of moles = mass/ molar mass
Number of moles = 0.43 g / 204.22 g/mol
Number of moles = 0.002 mol
Now we will compare the moles of C₈H₅KO₄ with NaOH.
C₈H₅KO₄ ; NaOH
1 : 1
0.002 : 0.002
Molarity of NaOH:
Molarity = number of moles / volume in litter
Molarity = 0.002 mol /0.0241 L
Molarity = 0.08 M
By the process of respiration and photosynthesis; carbon dioxide is obtained and also carbon dioxide in huge amount is produced from the industries which enters in the atmosphere. Carbon dioxide is one of the greenhouse gas.
Greenhouse gases are those gases which are able to trap the radiation in the atmosphere and which keeps Earth warmer. Thus, high levels of carbon dioxide gas keep the temperature of Earth warmer.
Answer:
305.88 g
Explanation:
4 Al + 3 O₂ → 2 Al₂O₃
First, we <u>convert 6 moles of aluminum (Al) into moles of aluminum oxide (Al₂O₃)</u>, using the <em>stoichiometric coefficients</em>:
6 mol Al *
= 3 mol Al₂O₃
Finally we <u>convert 3 moles of aluminum oxide into grams</u>, using its<em> molar mass</em>:
3 mol Al₂O₃ * 101.96 g/mol = 305.88 g
Main Answer: The standard electrode potential of galvanic cell constructed from barium and manganese electrode is 4.097.
Explanation:
When the galvanic cell constructed between Manganese and Barium, the half reactions will be as follows:
Mn2+(aq) + 2e-⟶ Mn(s) E1 = −1.185
Ba2+(aq) + 2e-⟶ Ba(s) E2 = −2.912
By considering the above two reactions, the standard electrode potential can be calculated.
The galvanic cell standard electrode potential is given by E1 + E2 = 1.185 + 2.912 = 4.097 volts
What is standard electrode potential?
Standard electrode potential is defined as the measure of reducing power of any compound or element. Its units are volts.
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