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Wewaii [24]
3 years ago
10

when a reactive metal is added to water, bubbles or fizzing can be observed. Explain the appearance of the bubbles​

Chemistry
1 answer:
MakcuM [25]3 years ago
7 0

Answer:

This is because of the release of hydrogen gas in the reaction.

Explanation:

Metals react with water and produce a metal oxide and hydrogen gas. It also starts floating due to the bubbles of hydrogen gas sticking to its surface.

For eg:

<u>2Mg. + 2H2O --------> 2MgOH + H2</u>

Here,

Metal taken is <u>magnesium(2Mg)</u> which when reacts with <u>water(2H2O)</u> to form its <u>oxide form (2MgOH)</u> and <u>hydrogen gas(H2)</u> is released which comes outside water as bubbles.

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The mass of the gases can be determined by the moles of the gas in the ideal equation. The mass of xenon difluoride at 0.799 atm is 0.011 gms.

<h3>What is an ideal gas equation?</h3>

An ideal gas equation gives the moles of the substance from the temperature, volume, and pressure of the gas. The ideal gas equation can be shown as:

n = PV ÷ RT

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Given,

Volume of xenon difluoride (V) = 0.223 L

Pressure of xenon difluoride (P) = 0.799 atm

Temperature of xenon difluoride (T) = 320.15 Kelvin

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The moles of the gas is calculated as:

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= 0.1781 ÷ 2661.72

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169.29 × 6.69 × 10⁻⁵ = 0.011 gm

Therefore, 0.011 gms is the mass of xenon difluoride.

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brainly.com/question/14189621

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