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Wewaii [24]
2 years ago
10

when a reactive metal is added to water, bubbles or fizzing can be observed. Explain the appearance of the bubbles​

Chemistry
1 answer:
MakcuM [25]2 years ago
7 0

Answer:

This is because of the release of hydrogen gas in the reaction.

Explanation:

Metals react with water and produce a metal oxide and hydrogen gas. It also starts floating due to the bubbles of hydrogen gas sticking to its surface.

For eg:

<u>2Mg. + 2H2O --------> 2MgOH + H2</u>

Here,

Metal taken is <u>magnesium(2Mg)</u> which when reacts with <u>water(2H2O)</u> to form its <u>oxide form (2MgOH)</u> and <u>hydrogen gas(H2)</u> is released which comes outside water as bubbles.

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Given the following balanced equation determine the amount of MgCl2 that can be produced from 65.0 grams of Mg. Mg + HCl --&gt;
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Answer:

Mg + HCL --> MgCl2 + H2

mass 65.0 mass 257.26

RFM 24 RFM 95

moles 2.708 moles 2.708

Explanation:

mass of MgCl = 257.26 grams

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2 years ago
Which of the following statements most likely
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Answer:

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Explanation:

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3 years ago
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5. What is the systemic name for the following structure?
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5 0
2 years ago
Calculate for the following electrochemical cell at 25°C, Pt H2(g) (1.0 atm) H (0.010 M || Ag (0.020 M) Ag if E (H) - +0.000 V a
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The values of standard reduction electrode potential of the cell are:

E^0_{[H^{+}/H_2]}=+0.00V

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From the cell representation we conclude that, the hydrogen (H) undergoes oxidation by loss of electrons and thus act as anode. Silver (Ag) undergoes reduction by gain of electrons and thus act as cathode.

The half reaction will be:

Reaction at anode (oxidation) : H_2\rightarrow 2H^{+}+2e^-    

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The balanced cell reaction will be,  

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Now we have to calculate the standard electrode potential of the cell.

E^o_{cell}=E^o_{cathode}-E^o_{anode}

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4 0
3 years ago
How do evaporation and condensation relate to heat
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