Answer:
temperature 3000 km below the surface of earth is varied, it's harder to know the actual temperature, it can be found around 3,000 - 3,500 degrees Celsius
Answer:
The correct answer is - yes, 4.57 g of solute per 100 ml of solution
Explanation:
The correct answer is yes we can calculate the solubility of X in the water at 22.0°C. The salt will remain after the evaporate from the dissolved and cooled down at 26°C.
Then, the amount of solute dissolved in the 700 ml solution at 26°C is the weighed precipitate: 0.032 kg = 32 g.
Then solublity will be :
32. g solute / 700 ml solution = y / 100 ml solution
⇒ y = 32. g solute × 100 ml solution / 700 ml solution = 4.57 g.
Thus, the answer is 4.57 g of solute per 100 ml of solution.
Answer:
Explanation:
We will need a balanced chemical equation with masses and molar masses, so, let's gather all the information in one place.
M_r: 32 60
CH₃OH + CO ⟶ CH₃COOH
m/g: 160
(a) Moles of CH₃OH
(b) Moles of CH₃COOH
(c) Mass of CH₃COOH
Emulsions are an example of colloids<span> composed of tiny particles </span>suspended<span> in another immiscible (unmixable) material. An emulsion is a </span>suspension<span> of two liquids that usually do not mix together. These liquids that do not mix are said to be immiscible. An example would be </span>oil and water<span>.
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