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myrzilka [38]
3 years ago
14

Please Help

Chemistry
1 answer:
rewona [7]3 years ago
7 0

Answer:

The correct answer is - they can create genetic diversity as well and reproduce without mate when necessary.

Explanation:

Sexual reproduction provides an organism with genetic diversity and variation by the process and it required two mates and a longer time to pollination and fertilization and is used in normal conditions.

In case of a threat, such organisms use asexual reproduction to increase their number as in asexual reproduction no need of mate, an organism can grow and increase on its own it provides to not to exitinct.

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What happens to the potassium atom when it reacts with the chlorine atom? What is the electron configuration of the potassium af
hodyreva [135]

Answer:

See explanation

Explanation:

Potassium is a metal. Remember that metals are electropositive in nature. This implies that they give out electrons when they undergo ionic bonding with nonmetals.

Chlorine is a nonmetal. So the bond between chlorine and potassium is ionic.  Potassium gives out one electron to chlorine and the both ions now attain a stable octet.

The electronic configuration of potassium is [Ar]4s1. After giving out an electron to chlorine in an ionic bond, its electronic configuration is now [Ar].

3 0
2 years ago
What is the h+ oh- and poh of solution with ph=3.67
Alexxx [7]
Hi I don’t know the answer is I don’t know but I hope someone helps u ph=3.67
7 0
2 years ago
A gas at 200 K occupies a volume of 350 ml. What temperature is needed to increase the volume
Rudik [331]

Answer: Temperature in constant pressure is 286 K

Explanation: If pressure remains constant, then V/T = constant.

V1 = 350 ml and T1 = 200 K and V2 = 500 ml.  V1/T1 = V2/T2

and T2 = T1· V2 / V1 = 200 K · 500 ml / 300 ml = 285,7 K

5 0
3 years ago
When an electron in a 2p orbital of a particular atom makes a transition to the 2s orbital, a photon of approximate wavelength 6
Mariulka [41]

Answer:

The energy difference between these 2p and 2s orbitals is 3.07\times 10^{-19} J

Explanation:

Wavelength of the photon emitted = \lambda =646.3 nm =646.3\times 10^{-9} m

Energy of the photon will corresponds to the energy difference between 2p and 2s orbital = E

Energy of the photon is given by Planck's equation:

E=\frac{hc}{\lambda }

h = Planck's constant = 6.626\tiomes 10^{-34} Js

c = Speed of the light = 3\times 10^8 m/s

E=\frac{6.626\tiomes 10^{-34} Js\times 3\times 10^8 m/s}{646.3\times 10^{-9} m}

E=3.07\times 10^{-19} J

The energy difference between these 2p and 2s orbitals is 3.07\times 10^{-19} J

3 0
3 years ago
Lt takes 4 hr 39 min for a 2.00-mg sample of radium-230 to decay to 0.25 mg. what is the half-life of radium-230?
Rufina [12.5K]
Radioactive decay => C = Co { e ^ (- kt) |

Data:

Co = 2.00 mg
C = 0.25 mg
t = 4 hr 39 min

Time conversion: 4 hr 39 min = 4.65 hr

1) Replace the data in the equation to find k

C = Co { e ^ (-kt) } => C / Co = e ^ (-kt) => -kt = ln { C / Co} => kt = ln {Co / C}

=> k = ln {Co / C} / t =  ln {2.00mg / 0.25mg} / 4.65 hr = 0.44719

2) Use C / Co  = 1/2 to find the hallf-life

C / Co = e ^ (-kt) => -kt = ln (C / Co)

=> -kt = ln (1/2) => kt = ln(2) => t = ln (2) / k

t = ln(2) / 0.44719 = 1.55 hr.

Answer: 1.55 hr
6 0
3 years ago
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