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vladimir1956 [14]
3 years ago
8

When an electron in a 2p orbital of a particular atom makes a transition to the 2s orbital, a photon of approximate wavelength 6

46.3 nm is emitted. The energy difference between these 2p and 2s orbitals is:_________a. 3.07 Ã 10^â28 Jb. 3.07 Ã 10^â19 Jc. 3.07 Ã 10^â17 Jd. 1.28 Ã 10^â31 Je. none of these
Chemistry
1 answer:
Mariulka [41]3 years ago
3 0

Answer:

The energy difference between these 2p and 2s orbitals is 3.07\times 10^{-19} J

Explanation:

Wavelength of the photon emitted = \lambda =646.3 nm =646.3\times 10^{-9} m

Energy of the photon will corresponds to the energy difference between 2p and 2s orbital = E

Energy of the photon is given by Planck's equation:

E=\frac{hc}{\lambda }

h = Planck's constant = 6.626\tiomes 10^{-34} Js

c = Speed of the light = 3\times 10^8 m/s

E=\frac{6.626\tiomes 10^{-34} Js\times 3\times 10^8 m/s}{646.3\times 10^{-9} m}

E=3.07\times 10^{-19} J

The energy difference between these 2p and 2s orbitals is 3.07\times 10^{-19} J

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Calculate the specific heat capacity for a 15.3-g sample of gold that absorbs 87.2 J when its temperature increases from 35.0 °C
diamong [38]

Answer:

The specific heat of gold is 0.129 J/g°C

Explanation:

Step 1: Data given

Mass of gold  = 15.3 grams

Heat absorbed = 87.2 J

Initial temperature = 35.0 °C

Final temperature = 79.2 °C

Step 2:

Q = m*c*ΔT

⇒ Q =the heat absorbed = 87.2 J

⇒ m = the mass of gold = 15.3 grams

⇒ c = the specific heat of gold = TO BE DETERMINED

⇒ ΔT = The change in temperature = T2 - T1 = 79.2 - 35.0 = 44.2 °C

87.2 J = 15.3g * c * 44.2°C

c = 87.2 / (15.3 * 44.2)

c = 0.129 J/g°C

The specific heat of gold is 0.129 J/g°C

4 0
3 years ago
Please select the word from the list that best fits the definition
nika2105 [10]

An occluded front is well known to bring a large amount of rain and snow (Option F).

<h3>What is an occluded front?</h3>

An occluded front is a mass of air capable of bringing precipitation in the form of liquid water (rain) or snow.

This meteorological phenomenon (occluded front) is formed by warm air trapped with cold air.

In conclusion, an occluded front is well known to bring a large amount of rain and snow (Option F).

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6 0
1 year ago
One method for preparing pure iron from Fe2O3 is by reaction with carbon monoxide.Fe2O3(s)+CO(g)→Fe(s)+CO2(g) How many moles of
larisa [96]

Answer:

The 2292 moles of CO are needed to react completely with 122 Kg of Fe₂O₃.

Explanation:

Given data:

Mass of Fe₂O₃ = 122 Kg ( 122×1000 =  122000 g)

Moles of CO = ?

Solution:

Chemical equation:

Fe₂O₃ + 3CO  → 2Fe + 3CO₂

Number of moles of  Fe₂O₃:

Number of moles = mass/ molar mass

Number of moles = 122000 g /159.69 g/mol

Number of moles = 764 mol

Now we will compare the moles of Fe₂O₃ with CO.

                               Fe₂O₃            :            CO  

                                  1                  :             3

                               764                :             3×764  =2292 mol

The 2292 moles of CO are needed to react completely with 122 Kg of Fe₂O₃.

6 0
3 years ago
All of the following conditions of STP are true except A. 101.3 kPa B. 273.15 K C. 22.4 L D. 3.81 kPa
kaheart [24]
  3.81   kpa  is  the  condition   which  is  not  true   at  STP

According  to  IUPAC  the  standard  temperature  and  pressure  that  is  STP  the  temperature  is   273.15  k  or  0   degrees  celsius .  and  the  absolute  temperature   of   101.325 Kpa   or  1  atm.  In  addition at STP   the  volume of  ideal  gas  is  22.4 
8 0
3 years ago
3 waves are shown with a line through their center. The bottom of the first wave is labeled C. A bracket labeled D connects the
Likurg_2 [28]

Answer:Label the parts of this wave.

A:  

✔ crest

B:  

✔ amplitude

C:  

✔ trough

D:  

✔ wavelength

Explanation:

8 0
2 years ago
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