Answer:
using Pythagoras rule, 16^2 -7^2 =a^2
so 256-49 = 297.
√207 =14.38 to the nearest tenth of an inch is 14inch.which is your answer
The lengths of the other two sides of the right triangle are 12 and 13
<h3>Pythagorean theorem </h3>
From the question, we are to determine the lengths of the other sides of the triangle
From the given information,
The other sides have lengths that are consecutive integers
Thus,
If the length of the other side is x
Then,
The hypotenuse will be x + 1
By the <em>Pythagorean theorem</em>, we can write that
(x+1)² = x² + 5²
(x+1)(x+1) = x² + 25
x² + x + x + 1 = x² + 25
x² - x² + x + x = 25 - 1
2x = 24
x = 24/2
x = 12
∴ The other leg of the right triangle is 12
Hypotenuse = x + 1 = 12 + 1 = 13
Hence, the lengths of the other two sides are 12 and 13
Learn more on Pythagorean theorem here: brainly.com/question/4584452
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Answer:
ok so the probility of gettting one white fish is
13/23
and if we take out one white fish the problity is
12/22
so we just multiply
12/22*13/23=0.30830039525
so the problity is 0.30 if you choose two fish you will get white for both
Using the graph, it is found that 976 passengers had carry-on luggage that weighed less than 20 lb.
<h3>Graph:</h3>
The graph is not given in this problem, but an internet search indicates that the information it contains is as follows:
- 120 passengers carry luggage of 4 lb or less.
- 222 passengers carry luggage between 5 lb and 9 lb.
- 378 passengers carry luggage between 10 lb and 14 lb.
- 256 passengers carry luggage between 15 lb and 19 lb.
- 90 passengers carry luggage between 20 lb and 24 lb.
- 40 passengers carry luggage between 25 lb or more.
Hence, the number of passengers with luggage below 20 lb is:

976 passengers had carry-on luggage that weighed less than 20 lb.
A similar problem, also involving the use of graph, is given at brainly.com/question/25836450
Answer:

Step-by-step explanation:
see the attached figure to better understand the problem
we know that
The area of triangle ABC applying the law of sines is equal to

substitute the given values

