c'mon bro you can't be this helpless
odd, even, even, even, even
Newton is 762 Km east of Mayfield.
I send you a file wich the answer.
Answer:
Step-by-step explanation:
a. Profit, p, earned from selling x hats when hat will be sold for $12 each:
p = 12x
b. To recover the cost of making the 200 hats which is $1500, profit, p >= cost:
p = 12x >= 1500
x >= 1500/12 = 12.5
So the minimum number of hats that must be sold = 13
c. New hat price = $15 so p = 15x
p = 15x >= 1500
x >= 1500/15 = 10
So the new minimum = 10 which is 3 fewer.
This is a sum and difference problem, with the equations
R-N=35
R+N=635
The solution of which is
R=(635+35)/2=335
N=(635-35)/2=300
In general, the sum and difference problem can be solved (most of the time mentally) using
Larger number = (sum + difference)/2
Smaller number = (sum - difference)/2
