All categories

3 years ago

Font

1 answer:

7 0

Answer: 1. Complete the following chart for a pendulum: Trial Period String Length Mass of Bob Planet A 1.5 m 1.5 kg. Earth B 1.5 m 3.0 kg. Earth 25 s

1 answer

1 vote:

prolly a beacuse the momentuem the car has increases while going down hill...

Explanation:

You might be interested in

A friend says that the reason one's hair stands out while touching a charged Van de Graaff generator is simply that the hair str

Llana [10]

Answer:

Explanation:

Yes I agree with the statement .

When a person who is perfectly insulated from the earth , touches a Van de Graaff , his body acquires charge . when the hair acquires it, it stands out due to mutual repulsion . It is to be noted here that at pointed areas on a surface , there is larger accumulation of charge. Accumulation of charge is greater at hair tops .

It is also a general observation that when a bird sits on high tension wire , his feather stands out due to the same reason.

5 0

3 years ago

Explain two reasons why sea ice so important to a polar bear.

Zolol [24]

This loss of stable old ice has set up additional losses of sea ice cover each summer because the thinner younger ice is more easily melted during the recent warmer summers. Because of their dependence upon the sea ice for food, these changes can directly affect the carrying capacity of the Arctic for polar bears. Mark this as the brainliest answer please

6 0

3 years ago

Ask Your Teacher In Example 24.6, we found that the electric field of a charged disk approaches that of a charged particle for d

Ulleksa [173]

Answer: E = 7394.6N/C

Explanation:

Please find the attached file for the solution

8 0

3 years ago

A sphere of radius 5.15 cm and uniform surface charge density +12.1 µC/m2 exerts an electrostatic force of magnitude 35.9 ✕ 10-3

rosijanka [135]

The radius of the sphere is r=5.15 cm=0.0515 m, and its surface is given by
$A=4 \pi r^2 = 4 \pi (0.0515 m)^2 = 0.033 m^2$

So the total charge on the surface of the sphere is, using the charge density
$\rho=+1.21 \mu C/m^2 = +1.21 \cdot 10^{-6} C/m^2$ :
$Q= \rho A = (+1.21 \cdot 10^{-6} C/m^2)(0.033 m^2)=4.03 \cdot 10^{-8}C$

The electrostatic force between the sphere and the point charge is:
$F=k_e \frac{Qq}{r^2}$
where
ke is the Coulomb's constant
Q is the charge on the sphere
$q=+1.75 \muC = +1.75 \cdot 10^{-6}C$ is the point charge
r is their separation

Re-arranging the equation, we can find the separation between the sphere and the point charge:
$r=\sqrt{ \frac{k_e Q q}{F} }= \sqrt{ \frac{(8.99 \cdot 10^9 Nm^2 C^{-2})(4.03 \cdot 10^{-8} C)(1.75 \cdot 10^{-6}C)}{35.9 \cdot 10^{-3}N} }=0.133 m=13.3 cm$

8 0

3 years ago

A 68.5kg astronaut floating motionless next to the space station throws a 2.25kg tool away from her at 3.20m/s. With what speed

valkas [14]

Answer:

-0.105 m/s

Explanation:

Given that

Mass of the astronaut, m(a) = 68.5 kg

Mass of the tool, m(t) = 2.25 kg

Speed of the tool after it is thrown, v(t) = 3.20 m/s

We know that momentum of a particle,

p = mv

See the attachment for calculations

Therefore, the speed is 0.105 m/s and it moves in the opposite direction.

5 0

4 years ago