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german
3 years ago
6

Is microorganisms bigger or particles bigger

Chemistry
2 answers:
Vinil7 [7]3 years ago
6 0

Answer:

particles bigger

Explanation:

Even when compared with animal cells, microorganisms become smaller. They are about 1/10 the size of a typical human cell. Therefore, compared with human-sized animal cells, the size of bacteria (such as bacterial cells) will be the size of a cat or puppy. The size of the virus is about 1/10 of that of other microorganisms such as bacteria.

Hope it helps. If not, I'm so sorry.

slega [8]3 years ago
6 0

Answer:

particles are bigger than microorganism

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Answer:

m_{H2SO4 = 61.25 g

m_{Na2SO4} = 88.75 g

Explanation:

m_{NaOH} = \frac{200 . 25 }{100} = 50 g

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2NaOH + H2SO4 ⇒ Na2SO4 + 2H2O

   2        :     1           :      1         :    2

 1.25                                                       (moles)

⇒  n_{H2SO4} = 1.25 × 1 ÷ 2 = 0.625 (moles) ⇒ m_{H2SO4} = 0.625 × 98 = 61.25 g

    n_{Na2SO4} = 1.25 × 1 ÷ 2 = 0.625 (moles) ⇒m_{Na2SO4} = 0.625 × 142 = 88.75 g

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3 years ago
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3 years ago
500 mL of water is added to 400 mL of 0.35 M HCl. Find the concentration of the diluted solution.
jarptica [38.1K]

The concentration of diluted solution is 0.16 M

<u>Explanation:</u>

As, the number of moles of diluted solution and concentrated solution will be same.

So, the equation used to calculate concentration will be:

M_1V_1=M_2V_2

where,

M_1\text{ and }V_1 are the molarity and volume of the concentrated HCl solution

M_2\text{ and }V_2 are the molarity and volume of diluted HCl solution

We are given:

M_1=0.35M\\V_1=400mL\\M_2=?M\\V_2=(500+400)mL=900mL

Putting values in above equation, we get:

0.35\times 400=M_2\times 900\\\\M_2=\frac{0.35\times 400}{900}=0.16M

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3 years ago
A sample of nitrogen gas had a volume of 500. mL, a pressure in its closed container of 740 torr, and a temperature of 25 °C. Wh
iren2701 [21]

Answer:  Thus the new volume of the gas is 530  ml

Explanation:

Combined gas law is the combination of Boyle's law, Charles's law and Gay-Lussac's law.

The combined gas equation is,

\frac{P_1V_1}{T_1}=\frac{P_2V_2}{T_2}

where,

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P_2 = final pressure of gas = 760 torr

V_1 = initial volume of gas = 500 ml

V_2 = final volume of gas = ?

T_1 = initial temperature of gas = 25^oC=273+25=298K

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Now put all the given values in the above equation, we get:

\frac{740\times 500}{298}=\frac{760\times V_2}{323}

V_2=530ml

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6 0
3 years ago
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