Iron has a mass of 7.87 g per cubic centimeter of volume, and the mass of an iron atom is 9.27 × 10-26 kg. If you simplify and t
reat each atom as a cube, (a) what is the average volume (in cubic meters) required for each iron atom and (b) what is the distance (in meters) between the centers of adjacent atoms?
Known values; mass per / volume and mass of each atom
average volume=<span> volume per atom. </span> <span>density*mass per atom = volume per atom </span>
<span>1cm^3 / 7.87 gram * 9.27 *10^-26 kg /atom* 1000 gram / kg= </span>=<span>1.178 * 10^-22 cm^3 per atom </span>
<span>Convert that to mass </span> <span>1 cm^3 * (1 m / 100 cm)^3 </span> average volume= <span>1.178 *10^-29 m^3 per atom </span>
<span>distance: </span>
<span>Volume of a cube is L^3 </span>
<span>so L = (1.178*10^-29)^(1/3) </span>
<span>Half way through the cube is distance 1/2 L. </span> <span>Second cube is 1/2 L </span> <span>So distance between the center of 2 cubes = L </span>
Knowing that these metals are infact good conductors of electricity we can infer that metals are able to hold and conduct certain temperatures. Another thing we can infer is that these good conductors can be used in connection to transferring energy or electricity.
