Iron has a mass of 7.87 g per cubic centimeter of volume, and the mass of an iron atom is 9.27 × 10-26 kg. If you simplify and t
reat each atom as a cube, (a) what is the average volume (in cubic meters) required for each iron atom and (b) what is the distance (in meters) between the centers of adjacent atoms?
Known values; mass per / volume and mass of each atom
average volume=<span> volume per atom. </span> <span>density*mass per atom = volume per atom </span>
<span>1cm^3 / 7.87 gram * 9.27 *10^-26 kg /atom* 1000 gram / kg= </span>=<span>1.178 * 10^-22 cm^3 per atom </span>
<span>Convert that to mass </span> <span>1 cm^3 * (1 m / 100 cm)^3 </span> average volume= <span>1.178 *10^-29 m^3 per atom </span>
<span>distance: </span>
<span>Volume of a cube is L^3 </span>
<span>so L = (1.178*10^-29)^(1/3) </span>
<span>Half way through the cube is distance 1/2 L. </span> <span>Second cube is 1/2 L </span> <span>So distance between the center of 2 cubes = L </span>
