Question

Iron has a mass of 7.87 g per cubic centimeter of volume, and the mass of an iron atom is 9.27 × 10-26 kg. If you simplify and treat each atom as a cube, (a) what is the average volume (in cubic meters) required for each iron atom and (b) what is the distance (in meters) between the centers of adjacent atoms?

Answer 1

Known values; mass per / volume and mass of each atom 

average volume= volume per atom. 
density*mass per atom = volume per atom 

1cm^3 / 7.87 gram * 9.27 *10^-26 kg /atom* 1000 gram / kg=
=1.178 * 10^-22 cm^3 per atom 

Convert that to mass 
1 cm^3 * (1 m / 100 cm)^3 
 average volume= 1.178 *10^-29 m^3 per  atom 

distance: 

Volume of a cube is L^3 


so L = (1.178*10^-29)^(1/3) 

Half way through the cube is distance 1/2 L. 
Second cube is 1/2 L 
So distance between the center of 2 cubes = L 

=2.28 *10^-10 m