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Dmitry_Shevchenko [17]
3 years ago
14

Which of the following energy resources does not produce greenhouse

Physics
1 answer:
Inessa [10]3 years ago
7 0

Answer:

Geothermal

Explanation:

Geothermal is obtained from the heat from the ground which makes it friendly

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How does the sun's heat affect the humidity of a place​
Sunny_sXe [5.5K]

Answer:

the sun's heat affects humidity of how warm the air feels to us.

i tried

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I need help with homework! what should i choose as the greatest british invention?
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THE MINI Alec Issigonis, 1959
The Telephone Alexander Graham Bell, 1876

http://www.radiotimes.com/news/2013-01-08/the-50-greatest-british-inventions



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4 years ago
What is the unit of self inductance?
stira [4]

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The correct answer to that question is HENRY

6 0
3 years ago
A woman is applying 300N/m2 of pressure on to door with her hand. Her hand has area of 0.02m2. Work out the force being applied​
never [62]

Answer:

6N

Explanation:

Given parameters:

Pressure applied by the woman  = 300N/m²

Area = 0.02m²

Unknown:

Force applied  = ?

Solution:

Pressure is the force per unit area on a body

        Pressure  = \frac{force}{area}

         Force  = Pressure x area

        Force  = 300 x 0.02  = 6N

8 0
3 years ago
An electron enters a region of uniform electric field with an initial velocity of 64 km/s in the same direction as the electric
8090 [49]

Answer:

1.) 11 km/s

2.) 9.03 × 10^-5 metres

Explanation:

Given that an electron enters a region of uniform electric field with an initial velocity of 64 km/s in the same direction as the electric field, which has magnitude E = 48 N/C.

Electron q = 1.6×10^-19 C

Electron mass = 9.11×10^-31 Kg

(a) What is the speed of the electron 1.3 ns after entering this region?

E = F/q

F = Eq

Ma = Eq

M × V/t = Eq

Substitute all the parameters into the formula

9.11×10^-31 × V/1.3×10^-9 = 48 × 1.6×10^-19

V = 7.68×10^-18 /7.0×10^-22

V = 10971.43 m/s

V = 11 Km/s approximately

(b) How far does the electron travel during the 1.3 ns interval?

The initial velocity U = 64 km/s

S = ut + 1/2at^2

S = 64000×1.3×10^-6 + 1/2 × 8.4×10^12 × ( 1.3×10^-9)^2

S =8.32×10^-5 + 7.13×10^-6

S = 9.03 × 10^-5 metres

3 0
3 years ago
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