Answer:
The object is dropped, we know the initial velocity is zero. Once the object has left contact with whatever held or threw it, the object is in free-fall. Under these circumstances, the motion is one-dimensional and has constant acceleration of magnitude g.
No so sure
Explanation:
Hope it helps
The wave speed to this question is 400 meters
The horizontal component of the velocity of the ball is calculated by multiplying the speed by the cosine of the given angle.
x-component of speed = (31 m/s)(cos 35°)
= 25.39 m/s
Thus, the horizontal velocity component of the ball is 25.39 m/s.
Atoms is basic particles ,electrons,neutrons and the Regions of the atom are called electron shells and contain the electrons. So “a neutral core surrounded by mostly empty space”sounds pretty sure to me :)
Answer:
Magnitude of the force is 4350N
Explanation:
As the woman accelerates at a distance of 22 m to go from rest to 62.5 m / s, we can use the kinematics to find the acceleration
v² = v₀² + 2 a x
v₀ = 0
a = v² / 2x
a = 62.5²/(2 × 22)
a = 88.78m/s²
the time you need to get this speed
v = v₀ + a t
t = v / a
t = 62.5 / 88.78
t = 0.704s
Let's caculate the magnitude of the force
F = ma
= 49 × 88.78
= 4350.22
≅ 4350N
Magnitude of the force is 4350N
t = 1,025 s
a = 55.43 m / s²
