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coldgirl [10]
3 years ago
5

X + 1 / 8 y = 2 0 x + 1 / 4 y = 4

Mathematics
2 answers:
UkoKoshka [18]3 years ago
4 0

Answer:

Is that the question

Step-by-step explanation:

No seresly is that the question

IRINA_888 [86]3 years ago
3 0
Wait im not really sure whats the question your asking here
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A triangle has a base of 7 1/8 feet and height 7 1/5 ft. what is the area as a mixed number
sleet_krkn [62]

The answer is 25 13/20 square feet.

In order to complete this operation, it is first best to change your mixed numbers into improper fractions.

7 1/8 = 57/8

7 1/5 = 36/5

Now that we have these, we can put them into the triangle formula.

A = 1/2bh

A = (1/2)(57/8)(36/5)

A = 1026/40

You can then simplify this fraction by dividing the top and bottom by a factor of 2.

A = 513/20

Then, because we know 20 goes into 500, 25 times, we can pull that out and be left with a remainder of 13/20.

A = 25 13/20

8 0
3 years ago
Identify the constant terms of the expression 5x + 4y - 8x + 9x - 1
Elza [17]

Answer:

7

Step-by-step explanation:

5 0
3 years ago
Select the relationship that does represent a function.
maksim [4K]

Answer:

c

Step-by-step explanation:

3 0
3 years ago
A stack of blocks is 12.3 inches tall.If there are 10 blocks stacked one on top of the other, how tall is each block
timofeeve [1]
12.3/10=1.23

Answer 1.23
4 0
3 years ago
Find the area of the triangle ABC with the coordinates of A(10, 15) B(15, 15) C(30, 9).
lions [1.4K]

Check the picture below.  so, that'd be the triangle's sides hmmm so let's use Heron's Area formula for it.

~\hfill \stackrel{\textit{\large distance between 2 points}}{d = \sqrt{( x_2- x_1)^2 + ( y_2- y_1)^2}}~\hfill~ \\\\[-0.35em] ~\dotfill\\\\ (\stackrel{x_1}{10}~,~\stackrel{y_1}{5})\qquad (\stackrel{x_2}{15}~,~\stackrel{y_2}{15}) ~\hfill a=\sqrt{[ 15- 10]^2 + [ 15- 5]^2} \\\\\\ ~\hfill \boxed{a=\sqrt{125}} \\\\\\ (\stackrel{x_1}{15}~,~\stackrel{y_1}{15})\qquad (\stackrel{x_2}{30}~,~\stackrel{y_2}{9}) ~\hfill b=\sqrt{[ 30- 15]^2 + [ 9- 15]^2} \\\\\\ ~\hfill \boxed{b=\sqrt{261}}

(\stackrel{x_1}{30}~,~\stackrel{y_1}{9})\qquad (\stackrel{x_2}{10}~,~\stackrel{y_2}{5}) ~\hfill c=\sqrt{[ 10- 30]^2 + [ 5- 9]^2} \\\\\\ ~\hfill \boxed{c=\sqrt{416}} \\\\[-0.35em] ~\dotfill

\qquad \textit{Heron's area formula} \\\\ A=\sqrt{s(s-a)(s-b)(s-c)}\qquad \begin{cases} s=\frac{a+b+c}{2}\\[-0.5em] \hrulefill\\ a=\sqrt{125}\\ b=\sqrt{261}\\ c=\sqrt{416}\\ s\approx 23.87 \end{cases} \\\\\\ A\approx\sqrt{23.87(23.87-\sqrt{125})(23.87-\sqrt{261})(23.87-\sqrt{416})}\implies \boxed{A\approx 90}

6 0
1 year ago
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